Genetics: From Genes To Genomes (6th International Edition)
6th Edition
ISBN: 9781260041217
Author: Leland Hartwell Dr., ? Michael L. Goldberg Professor Dr., ? Janice Fischer, ? Leroy Hood Dr.
Publisher: Mcgraw-Hill
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Textbook Question
Chapter 10, Problem 4P
Which of the enzymes from the following list would you need to make a cDNA library? What is the function of those enzyme(s) in the process?
| a. | DNA polymerase |
| b. | RNA polymerase |
| c. | A restriction enzyme |
| d. | DNA ligase |
| e. | An aminoacyl-tRNA synthetase |
| f. | Peptidyl transferase |
| g. | Reverse transcriptase |
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Students have asked these similar questions
Which of the following sequences, when combined with itscomplement, would be clipped by a restriction endonuclease?a. ATCGATCGTAGCTA
b. AAGCTTCGAA
c. GAATTC
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Choose the combination of answers that most accurately completes the statement.Which of the following sequences, when combined with its complement, would be clipped by a restriction endonuclease? a. ATCGATCGTAGCTA c. GAATTC b. AAGCTTCGAA d. ACCATTGGA
Match the following polymerases with their function.
+ DNA Polymerase III
DNA polymerase I
+ RNA polymerase
+ RNA polymerase II
A. Polymerase responsible for proofreading
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B. Polymerase responsible for making
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D. Polymerase responsible for making
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Chapter 10 Solutions
Genetics: From Genes To Genomes (6th International Edition)
Ch. 10 - Prob. 1PCh. 10 - List three independent techniques you could use to...Ch. 10 - Figure 10.2a has numbers indicating the...Ch. 10 - Which of the enzymes from the following list would...Ch. 10 - Prob. 5PCh. 10 - a. What sequence information about a gene is...Ch. 10 - Why do geneticists studying eukaryotic organisms...Ch. 10 - Consider three different kinds of human libraries:...Ch. 10 - The human genome has been sequenced, but we still...Ch. 10 - This problem investigates issues encountered in...
Ch. 10 - For the sake of simplicity, Fig. 10.4 omitted one...Ch. 10 - Give two different reasons for the much higher...Ch. 10 - Using a cDNA library, you isolated two different...Ch. 10 - The figure that follows shows part of a modified...Ch. 10 - In Problem 14, cDNAs F and G could not be found in...Ch. 10 - Fig. 10.10 presents a model for exon shuffling in...Ch. 10 - An interesting phenomenon found in vertebrate DNA...Ch. 10 - a. If you found a zinc-finger domain which...Ch. 10 - Prob. 19PCh. 10 - In the human immune system, so-called B cells can...Ch. 10 - Chimpanzees have a set of hemoglobin genes very...Ch. 10 - Complete genome sequences indicate that the human...Ch. 10 - On your computers browser, view the page accessed...Ch. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Certain individuals with mild forms of...Ch. 10 - The 1 and 2 genes in humans are identical in their...Ch. 10 - Prob. 28P
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- A mutant DNA strand was transcribed then translated to proteins. a. What is the protein product of the mutant DNA strand? The sequence of the mutant strand is shown below: 5'-TGCCATAACTGTTCGTACTGGCAAATTGCC-3' 3'-ACGGTATTGACAAGCATGACCGTTTAACGG-5' b. The mutation altered the sequence of the wild type template DNA such that a degenerate codon for a basic amino acid in the wild type was converted to a non-degenerate codon resulting in the sequence for the mutant strand shown. What was the original amino acid? c. Compare the charges and pl of the mutant peptide and the normal (wild- type) peptide at physiological pH?arrow_forwardMatch the activity below with the correct enzyme. (You won't use all the enzymes listed.) RNA acts as a template for DNA synthesis: RNA directs the cutting of an RNA molecule at a precise location: RNA directs the cutting of an DNA molecule at a precise location: options: a. Small Nuclear Ribonuclear Protein (SNRNP) b. telomerase c. primase d. helicase e. CRISPR/Cas9arrow_forwardCertain restriction endonucleases produce cohesive (sticky) ends. This means that they: a. stick tightly to the ends of the DNA they have cut. b. cut both DNA strands at the same base pair. c. make a staggered double-strand cut, leaving ends with a few nucleotides of single-stranded DNA protruding. d. cut in regions of high GC content, leaving ends that can form more hydrogen bonds than ends of high AT content. e. cut in regions of high AT content, leaving ends that can form more hydrogen bonds than ends of high GC content.arrow_forward
- Restriction enzymes (type II) bind to their recognition site and A. begin elongation from it B. methylaet it C. cut inside it D. ligate itarrow_forwardIf you are a genetic engineer and you cloned your gene of interest in a plasmid and you want to know if the protein encoded by the cloned gene is expressed or not, which of the following methods is the right one to use? Select one: a. Northern blot b. Both Northern and Western blots c. Agarose gel with polyacrylamide d. Western blot e. Protein gel and northern blotarrow_forwardYou are performing a PCR reaction but unbeknownst to you, there is a significant pool of dUTP in the nucleotide mix (along with dCTP, dTTP, dATP, and dGTP). How might this affect your PCR product? a. If the PCR product was ligated into a plasmid and put into a cell, a totally different mRNA would be made from the insert compared to an insert made with T's. b. If the pool of dTTP ran out before the pool of dUTP, DNA replication could no longer occur. c. During the reaction, uracils incorporated into the product would cause the PCR product to degrade as it is being made. d. Uracil would be incorporated into the product and would lessen the affinity of any DNA binding proteins that might bind to the product in subsequent experiments. e. Nothing would happen since polymerases can't use dUTP to make DNA.arrow_forward
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- What are the sticky ends of the restriction fragments? Select one: a. The surfaces of sticky ends contain matching base pairs, allowing fragments to splice. b. The surfaces of sticky ends have glue like substance that allow fragments to splice. c. The surfaces of sticky ends contain the exact same nucleotides, allowing fragments to bond. d. The surfaces of sticky ends have velcro like structure, allowing fragments to bond.arrow_forwardHindIII is a restriction endonuclease that recognizes a palindrome sequence. Predict which one is the HindIII recognition site: a. AAGGTT b. AAGCTT c. AGCCGA d. AGCGCA e. AGCAGCarrow_forwardDescribe What are the sticky ends of the restriction fragments? Select one: a. The surfaces of sticky ends contain matching base pairs, allowing fragments to splice. b. The surfaces of sticky ends have glue like substance that allow fragments to splice. c. The surfaces of sticky ends contain the exact same nucleotides, allowing fragments to bond. d. The surfaces of sticky ends have velcro like structure, allowing fragments to bond.arrow_forward
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