Chapter 10.11B, Problem 10.25P

(a)

Interpretation Introduction

To determine: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound is to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.

(b)

Interpretation Introduction

To determine: The products from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The products from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound are to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.

(c)

Interpretation Introduction

To determine: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound is to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.

(d)

Interpretation Introduction

To determine: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound is to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.

(e)

Interpretation Introduction

To determine: The products from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The products from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound are to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.

(f)

Interpretation Introduction

To determine: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound.

Interpretation: The product from the reaction of ${\text{LiAlH}}_{\text{4}}$ with the given compound is to be stated.

Concept introduction: Lithium aluminum hydride ${\text{LiAlH}}_{\text{4}}$ is much stronger reducing reagent than sodium borohydride ${\text{NaBH}}_{\text{4}}$. It easily reduces less reactive carbonyl groups like carboxylic acids and esters and also reduces ketones and aldehyde.

It reduces aldehyde, carboxylic acids and esters to primary alcohol, and ketones to secondary alcohol.

The reaction of ${\text{LiAlH}}_{\text{4}}$ with aldehyde, carboxylic acids, esters and ketone is followed by the hydrolysis to give the product in the reaction.