Chapter 11, Problem 11.7YT

Interpretation Introduction

Interpretation:

The hypothetical two-step mechanism in which water adds across the double bond in equation $\text{11-13}$ according to the mechanism in equation $\text{11-3}$ is to be drawn. The ${\text{OH}}^{\text{-}}$ intermediate is to be identified. This mechanism is unfeasible whereas the same mechanism with HCl as the acid is feasible; the reason behind this is to be determined.

Concept introduction:

Electron rich compounds of hydrogen contain excess valence electrons to form covalent bonds. Electron-poor (electrophiles) substrates can accept an electron pair to form a new bond. They are attached by nucleophiles (electron rich). In alkene, the strong Bronsted acids such as HCl, HBr, HI, and ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ quickly add to the C=C functional group. The hydrogen and conjugate base of the acid forms covalent bond with the alkene molecule.