Complete the following table for the reaction
(a)
Interpretation:
To determine the rate for the given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 17QAP
Rate of reaction is
Explanation of Solution
Here the given chemical reaction is:
It is given that reaction is first order with respect to R and second order with respect with S. Thus, rate law for above reaction will be:
Here we have:
Concentration of R=0.200 M
Concentration of S = 0.200 M
Rate constant =1.49 L2/mol2.min
Rate of reaction = let it ‘r’
Plugging value in rate law expression:
(b)
Interpretation:
To determine the concentration of R in given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 17QAP
Concentration of R is
Explanation of Solution
Here the given chemical reaction is:
It is given that reaction is first order with respect to R and second order with respect with S. Thus, rate law for above reaction will be:
Here we have:
Concentration of R= let it ‘[R]’ mol/L
Concentration of S = 0.633 mol/L
Rate constant =0.42 L2/mol2.min
Rate of reaction = 0.833 mol/L.min
Plugging value in rate law expression:
(c)
Interpretation:
To determine the concentration of S in given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 17QAP
Concentration of S is
Explanation of Solution
Here the given chemical reaction is:
It is given that reaction is first order with respect to R and second order with respect with S. Thus, rate law for above reaction will be:
Here we have:
Concentration of R= 0.100 mol/L
Concentration of S = let it ‘[S]’ mol/L
Rate constant = 0.298 L2/mol2.min
Rate of reaction = 0.162 mol/L.min
Plugging value in rate law expression:
(d)
Interpretation:
To determine the rate constant in the given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 17QAP
Rate constant is
Explanation of Solution
Here the given chemical reaction is:
It is given that reaction is first order with respect to R and second order with respect with S. Thus, rate law for above reaction will be:
Here we have:
Concentration of R= 0.0500 mol/L
Concentration of S = 0.0911 mol/L
Rate constant = let it ‘k’ L2/mol2.min
Rate of reaction = 0.00624 mol/L.min
Plugging value in rate law expression:
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Chapter 11 Solutions
OWLV2 FOR MASTERTON/HURLEY'S CHEMISTRY:
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