(a)
Interpretation:
To determine the order of reaction with respect to each reactant in following reaction:
Concept introduction:
Rate of a
Mathematically,
Let’s say we have a reaction:
Answer to Problem 30QAP
Order of given reaction:
With respect to NO =4
With respect to O2 =1
Explanation of Solution
Given Information:
Here the chemical reaction is:
Experiment No. | Concentration of NO | Concentration of
|
Initial rate (mol/L.min) |
1 | 0.0244 | 0.0372 |
|
2 | 0.0244 | 0.0122 |
|
3 | 0.0244 | 0.0262 |
|
4 | 0.0732 | 0.0372 |
|
Let’s assume the reaction to be ‘t’ order with respect to NO and ‘y’ order with respect to O2.
Then, rate law for experiment 1, 2, 3 and 4 in above reaction will be;
Dividing (1) by (2) to get value of ‘y’.
Thus, order with respect to O2 is 1
Dividing (1) by (4) to get value of ‘t’.
Thus, order with respect to NO is 4.
(b)
Interpretation:
To write the rate expression for the given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective order of reaction.
Let’s say we have a reaction:
Answer to Problem 30QAP
Rate law expression for above reaction will be;
Explanation of Solution
Here the chemical reaction is:
Order of reaction with respect to NO = 4
Order of reaction with respect to O2 = 1
Let the rate constant be ‘k’.
Then, rate law expression for above reaction will be:
(c)
Interpretation:
To determine the rate constant and its unit for the given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective order of reaction.
Let’s say we have a reaction:
Answer to Problem 30QAP
Rate constant is
And its unit is
Explanation of Solution
Here the chemical reaction is:
Writing rate law for experiment 1 in above reaction will be;
Hence, the rate constant is
And its unit is
(d)
Interpretation:
To determine the rate of reaction at given concentration of reactants.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective order of reaction.
Let’s say we have a reaction:
Answer to Problem 30QAP
Rate of reaction is
Explanation of Solution
Here the chemical reaction is:
Rate law expression for above reaction:
Here we have:
[NO] = 0.0100 M
[O2 ] = 0.0462 M
Rate constant =
Plugging values in rate law as:
Hence, the rate of reaction is
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Chapter 11 Solutions
OWLV2 FOR MASTERTON/HURLEY'S CHEMISTRY:
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