The hypothetical reaction
min when [X] is 0.150 M and [Y] is 0.0800 M.
(a) What is the value for k?
(b) At what concentration of [Y] is the rate 0.00948 mol/L
min and [X] is 0.0441 M?
(c) At what concentration of [X] is the rate 0.0124 mol/L
min and
(a)
Interpretation:
To determine the value of rate constant for the given reaction.
Concept introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 22QAP
Rate constant for the given reaction is 4.05 L/mol.min
Explanation of Solution
Here the chemical reaction is:
Since the order of reaction with respect to X and Y is first order and second order respectively. Thus, rate law equation will look like:
Here we have:
[X] = 0.150 M
[Y] = 0.0800 M
Rate of reaction = 0.00389 mol/L.min
Plugging value of rate of reaction in equation 1 to get the value of rate constant as:
Hence, the rate constant for the given reaction is 4.05 L/mol.min
(b)
Interpretation:
To determine the concentration of Y when rate of reaction is 0.00948 mol/L.min and concentration of X is 0.0441 M.
Concept Introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 22QAP
The concentration of Y is 0.230 mol/L.
Explanation of Solution
Here the chemical reaction is:
Since the order of reaction with respect to ICl and H2 is first order and second order respectively. Thus, rate law equation will look like:
Here we have:
[X] = 0.0441 M
Rate of reaction = 0.00948 mol/L.min
Rate constant = 4.05 L/mol.s
Plugging value of rate of reaction in equation 1 to get the value of rate constant as:
Hence, the concentration of Y is 0.230 mol/L.
(c)
Interpretation:
To determine the concentration of X when rate of reaction is 0.0124 mol/L.min and concentration of Y is 2 times the concentration X i.e., [Y] = 2×[X].
Concept Introduction:
Rate of a chemical reaction: It tells us about the speed at which the reactants are converted into products.
Mathematically, rate of reaction is directly proportional to the product of concentration of each reactant raised to the power equal to their respective stoichiometric coefficients.
Let’s say we have a reaction:
Answer to Problem 22QAP
The concentration of X is
Explanation of Solution
Here the chemical reaction is:
Since the order of reaction with respect to ICl and H2 is first order and second order respectively. Thus, rate law equation will look like:
Here we have:
[Y] = 2[X]
Rate of reaction = 0.0124 mol/L.min
Rate constant = 4.05 L/mol.min
Plugging value of rate of reaction in equation 1 to get the value of rate constant as:
Hence, the concentration of X is
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Chapter 11 Solutions
OWLV2 FOR MASTERTON/HURLEY'S CHEMISTRY:
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