Concept explainers
(a)
To find: The discussion on the shape of each distribution.
(a)
Answer to Problem 29SR
The shape of each distribution is discussed.
Explanation of Solution
Given:
The distribution of the Peter’s and Paul’s distribution is given.
Calculation:
Draw the histogram of Peter’s article using the given data.
Figure 1
From the above graph, it is conclude that the distribution is positively skewed.
Draw the histogram of Paul’s article using the given data.
Figure 2
From the above graph, it is conclude that the distribution is symmetric.
Thus, the shape of each distribution is discussed.
(b)
To find: The comparison between distributions.
(b)
Answer to Problem 29SR
The comparison between distributions is discussed.
Explanation of Solution
Given:
The distribution of the Peter’s and Paul’s distribution is given.
Calculation:
The range of the Peter’s and the Paul’s articles is 64 and 53 respectively. The upper and lower quartile of Peter’s and the Paul’s articles is 33 and 34 respectively.
From above it is concluded that 75% of Paul’s article have more likes and hence are more popular.
Thus, the comparison between distributions is discussed.
Chapter 11 Solutions
Glencoe Algebra 2 Student Edition C2014
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