Chapter 11.4, Problem 55SR

a.

To determine

Use a graphing calculator to create a box-and-whisker plot.

Answer to Problem 55SR

  

Explanation of Solution

Given information:

The prices of entrees offered by a restaurant are shown,

  $\begin{array}{l}\text{ Prices }\left(\text{dollars}\right)\\ \begin{array}{cccc}11.25& 14.75& 9.00& 17.25\\ 19.75& 9.75& 20.25& 15.50\\ 16.50& 21.50& 10.25& 22.75\\ 12.75& 18.50& 23.00& 13.50\end{array}\end{array}$

Use a graphing calculator to create a box-and-whisker plot. Then describe the shape of the distribution.

Calculation:

Consider the table of entrees.

  $\begin{array}{l}\text{ Prices }\left(\text{dollars}\right)\\ \begin{array}{cccc}11.25& 14.75& 9.00& 17.25\\ 19.75& 9.75& 20.25& 15.50\\ 16.50& 21.50& 10.25& 22.75\\ 12.75& 18.50& 23.00& 13.50\end{array}\end{array}$

Use $TI-83$ calculator to create a box-and-whisker plot to start with ON key.

Press $\boxed{STAT}$ key to obtain the screen,

  

Click on the $\boxed{1}$ to edit the data.

  

Enter the data values and see the screen ,

  

Press $\boxed{2nd}+\boxed{Zoom}$ key and see the screen,

  

Press $\boxed{2nd}+\boxed{Y}$ also use arrow key to make the plot ON,

  

Press $\boxed{ZOOM}$ key to select number $9:ZoomStat$ .

  

Press $\boxed{ENTER}$ key to get the box-and-whisker plot.

  

Hence, the box-and-whisker plot is drawn.

b.

To determine

Describe the centre and spread of the data using either the mean or standard deviation.

Answer to Problem 55SR

  $\boxed{\overline{x}=\$16.02}$ , $\boxed{{\sigma }_x=\$4.52}$

Explanation of Solution

Given information:

The prices of entrees offered by a restaurant are shown,

  $\begin{array}{l}\text{ Prices }\left(\text{dollars}\right)\\ \begin{array}{cccc}11.25& 14.75& 9.00& 17.25\\ 19.75& 9.75& 20.25& 15.50\\ 16.50& 21.50& 10.25& 22.75\\ 12.75& 18.50& 23.00& 13.50\end{array}\end{array}$

Describe the centre and spread of the data using either the mean and standard deviation or the

five- number summary. Justify your choice.

Calculation:

Consider the graph.

  

Use $TI-83$ calculator to create a box-and-whisker plot to start with ON key.

Press $\boxed{STAT}$ and right arrow key to obtain the screen,

  

Select $1-Var$ by pressing $\boxed{ENTER}$ key when the pointer is on $1$ .press the $\boxed{ENTER}$ key again to get the screen.

  

Hence, from the screen it is clear that, mean of the data, is $\boxed{\overline{x}=\$16.02}$ and standard deviation is $\boxed{{\sigma }_x=\$4.52}$