McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Chapter 1.2, Problem 43AR

To determine

To find: The value of the variable from the equation 2(4d+4)=d+1 .

Expert Solution & Answer

Answer to Problem 43AR

The value of the variable is d=−1 .

Explanation of Solution

Given:

The equation is 2(4d+4)=d+1 .

Calculation:

Simplify the equation 2(4d+4)=d+1 as follows:

2(4d+4)=d+18d+8=d+18d−d=1−87d=−7d=−1

Thus, the value of the variable is d=−1 .

Chapter 1.2, Problem 42AR

Chapter 1.2, Problem 44AR

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

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