McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Chapter 1.4, Problem 38CE

To determine

To tell: whether OA→ and OB→ are opposite rays.

Expert Solution & Answer

Answer to Problem 38CE

Yes, we can conclude Rays OA and OB are opposite rays because point O is between points A and B.

Explanation of Solution

Given information:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.4, Problem 38CE

Rays are said to be opposite rays if they share a common endpoint O, and that endpoint is between (collinear with and in between) another point A, B on each ray.

Rays OA and OB point in opposite directions. Hence, they are 180° apart and form a straight angle.

A straight line is a basic assumption of geometry. It's one of the undefined terms.

Chapter 1.4, Problem 37CE

Chapter 1.4, Problem 1WE

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 1.1 - Prob. 1CE Ch. 1.1 - Prob. 2CE Ch. 1.1 - Prob. 3CE Ch. 1.1 - Prob. 4CE Ch. 1.1 - Prob. 5CE Ch. 1.1 - Prob. 6CE Ch. 1.1 - Prob. 7CE Ch. 1.1 - Prob. 8CE Ch. 1.1 - Prob. 1WE Ch. 1.1 - Prob. 2WE

Ch. 1.1 - Prob. 3WE Ch. 1.1 - Prob. 4WE Ch. 1.1 - Prob. 5WE Ch. 1.1 - Prob. 6WE Ch. 1.1 - Prob. 7WE Ch. 1.1 - Prob. 8WE Ch. 1.1 - Prob. 9WE Ch. 1.1 - Prob. 10WE Ch. 1.2 - Prob. 1CE Ch. 1.2 - Prob. 2CE Ch. 1.2 - Prob. 3CE Ch. 1.2 - Prob. 4CE Ch. 1.2 - Prob. 5CE Ch. 1.2 - Prob. 6CE Ch. 1.2 - Prob. 7CE Ch. 1.2 - Prob. 8CE Ch. 1.2 - Prob. 9CE Ch. 1.2 - Prob. 10CE Ch. 1.2 - Prob. 11CE Ch. 1.2 - Prob. 12CE Ch. 1.2 - Prob. 13CE Ch. 1.2 - Prob. 14CE Ch. 1.2 - Prob. 15CE Ch. 1.2 - Prob. 16CE Ch. 1.2 - Prob. 17CE Ch. 1.2 - Prob. 18CE Ch. 1.2 - Prob. 19CE Ch. 1.2 - Prob. 20CE Ch. 1.2 - Prob. 1WE Ch. 1.2 - Prob. 2WE Ch. 1.2 - Prob. 3WE Ch. 1.2 - Prob. 4WE Ch. 1.2 - Prob. 5WE Ch. 1.2 - Prob. 6WE Ch. 1.2 - Prob. 7WE Ch. 1.2 - Prob. 8WE Ch. 1.2 - Prob. 9WE Ch. 1.2 - Prob. 10WE Ch. 1.2 - Prob. 11WE Ch. 1.2 - Prob. 12WE Ch. 1.2 - Prob. 13WE Ch. 1.2 - Prob. 14WE Ch. 1.2 - Prob. 15WE Ch. 1.2 - Prob. 16WE Ch. 1.2 - Prob. 17WE Ch. 1.2 - Prob. 18WE Ch. 1.2 - Prob. 19WE Ch. 1.2 - Prob. 20WE Ch. 1.2 - Prob. 21WE Ch. 1.2 - 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Prob. 5WE Ch. 1.3 - Prob. 6WE Ch. 1.3 - Prob. 7WE Ch. 1.3 - Prob. 8WE Ch. 1.3 - Prob. 9WE Ch. 1.3 - Prob. 10WE Ch. 1.3 - Prob. 11WE Ch. 1.3 - Prob. 12WE Ch. 1.3 - Prob. 13WE Ch. 1.3 - Prob. 14WE Ch. 1.3 - Prob. 15WE Ch. 1.3 - Prob. 16WE Ch. 1.3 - Prob. 17WE Ch. 1.3 - Prob. 18WE Ch. 1.3 - Prob. 19WE Ch. 1.3 - Prob. 20WE Ch. 1.3 - Prob. 21WE Ch. 1.3 - Prob. 22WE Ch. 1.3 - Prob. 23WE Ch. 1.3 - Prob. 24WE Ch. 1.3 - Prob. 25WE Ch. 1.3 - Prob. 26WE Ch. 1.3 - Prob. 27WE Ch. 1.3 - Prob. 28WE Ch. 1.3 - Prob. 29WE Ch. 1.3 - Prob. 30WE Ch. 1.3 - Prob. 31WE Ch. 1.3 - Prob. 32WE Ch. 1.3 - Prob. 33WE Ch. 1.3 - Prob. 34WE Ch. 1.3 - Prob. 35WE Ch. 1.3 - Prob. 36WE Ch. 1.3 - Prob. 37WE Ch. 1.3 - Prob. 38WE Ch. 1.3 - Prob. 39WE Ch. 1.3 - Prob. 40WE Ch. 1.3 - Prob. 41WE Ch. 1.3 - Prob. 42WE Ch. 1.3 - Prob. 43WE Ch. 1.3 - Prob. 44WE Ch. 1.3 - Prob. 45WE Ch. 1.3 - Prob. 46WE Ch. 1.3 - Prob. 47WE Ch. 1.3 - Prob. 48WE Ch. 1.4 - Prob. 1CE Ch. 1.4 - Prob. 2CE Ch. 1.4 - Prob. 3CE Ch. 1.4 - Prob. 4CE Ch. 1.4 - Prob. 5CE Ch. 1.4 - 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To tell: whether O A → and O B → are opposite rays.