Concept explainers
a
To sketch: a line which shows a set of points equidistant from F and T as shown in the figure below.
a
Explanation of Solution
Given information: Points F,T and P are shown as below in the diagram and a sketch has to be made of a line that specifies a set of points which are equidistant from F and T .
Sketch: Take a centimeter ruler and find a point midway between F and T and mark it. Now draw a line through that point perpendicular to the line joining F and T, which is the required line.
Interpretation: The required line is equidistant from points F and T which can be checked using a centimeter ruler.
b
To sketch: a
b
Explanation of Solution
Given information: Points F, T and P are shown as below in the diagram and a sketch has to be made of a circle whose radius is 2 cm and the center is at P as shown below.
Sketch: Use a ruler to set the distance from the point of the compass needle to the pencil's lead at 2 cm. Place the compass needle at P and rotate it about 360 degrees. The required object in the plane is a circle of radius 2 cm.
Interpretation: The circle so formed has a radius of 2 cm which can be checked by a centimeter ruler.
c
To sketch: the points 2 cm from P which are equidistant from F and T as shown in the figure below,
c
Explanation of Solution
Given information: Points F,T and P are shown as below in the diagram; it is to be found that how many points are equidistant from F and T and are also 2 cm away from P.
Graph: Take a centimeter ruler and find a point midway between F and T and mark it. Now draw a line through that point perpendicular to the line joining F and T. Use a ruler to set the distance from the point of the compass needle to the pencil's lead at 2 cm. Place the compass needle at P and rotate it about 360 degrees. The required object in the plane is a circle of radius 2 cm. But it does not cross the line joining F and T even once.
So there are no point of intersection obtained as a result.
Interpretation: There are no points which are equidistant from F and T and 2 cm away from P.
Chapter 1 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
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