McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 1.5, Problem 18WE

(a)

To determine

To check: The postulate that guarantees the existence of the plane ABC, ABD, ACD, BCD .

(a)

Expert Solution
Check Mark

Answer to Problem 18WE

It is the postulate 7.

Explanation of Solution

Given information:

Consider the statements below and associated figure

Points A , B , C and D are four non coplanar points

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.5, Problem 18WE , additional homework tip  1

Formula used:

Through any 3 non collinear points there is exactly one plane

Calculation:

From Postulate 7, through any 3 non collinear points there is exactly one plane. From the figure, points A , B , C and D are non collinear points, therefore from above argument there will be exactly one plane through points A,B,C and A,B,D and A,C,D and B,C,D

Hence, the answer is postulate 7.

Conclusion:

It is the postulate 7.

(b)

To determine

To describe:The ruler postulate that guarantees the existence of point P between A and D .

(b)

Expert Solution
Check Mark

Explanation of Solution

Given information:

Consider the statements below and associated figure

Points A, B, C and D are four non coplanar points

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.5, Problem 18WE , additional homework tip  2

Formula used:

Through any 3 non collinear points there is exactly one plane

Calculation:

By Ruler Postulate, the distance between any two points equals the absolute value of the difference of coordinates. If P is between A and D , with the respective coordinates y, x , and z and assuming x < y < z

By the ruler postulate,

  AP=|yx|PD=|zy|AD=|zx|

But y-x is positive because x < y. By similar argument, z - y and z - x are positive.

Therefore,

  AP+PD=yx+zy=zxAP+PD=AD

Therefore, the assumption of P is between A and D is correct.

Hence, the answer is P between A and D is proved by ruler postulate.

Conclusion:

The answer is P between A and D is proved by ruler postulate.

(c)

To determine

To write:The postulate that guarantees the existence of BCP.

(c)

Expert Solution
Check Mark

Answer to Problem 18WE

The answer is postulate 7.

Explanation of Solution

Given information:

Consider the statements below and associated figure

Points A, B, C and D are four non coplanar points.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.5, Problem 18WE , additional homework tip  3

Formula used:

Through any 3 non collinear points there is exactly one plane

Calculation:

From Postulate 7, through any 3 non collinear points there is exactly one plane. From the figure, points B, C and P are non collinear points therefore from above argument there will be exactly one plane through points B, C, P

Hence, the answer is postulate 7.

Conclusion:

The answer is postulate 7.

(d)

To determine

To show:how there are infinite number of planes through BC¯

(d)

Expert Solution
Check Mark

Answer to Problem 18WE

The infinite number of point on AD¯ to form 3 non-collinear points with B and C and postulate 7 guarantees the existence of a unique plane through each set of the three points.

Explanation of Solution

Given information:

Consider the statements below and associated figure

Points A, B, C and D are four non coplanar points

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.5, Problem 18WE , additional homework tip  4

Formula used:

Through any 3 non collinear points there is exactly one plane

Calculation:

From the definition, a line segment consists of infinite number of points. This implies, there are an infinite number of points on AD¯ . Therefore, there are an infinite number of non collinear points to match up with B and C.

From Postulate 7, through any 3 non collinear points there is exactly one plane which implies each set of the three points forms a unique plane.

Hence, the answer to is infinite number of point on AD¯ to form 3 non-collinear points with B and C and postulate 7 guarantees the existence of a unique plane through each set of the three points.

Conclusion:

The infinite number of point on AD¯ to form 3 non-collinear points with B and C and postulate 7 guarantees the existence of a unique plane through each set of the three points.

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 1.1 - Prob. 3WECh. 1.1 - Prob. 4WECh. 1.1 - Prob. 5WECh. 1.1 - Prob. 6WECh. 1.1 - Prob. 7WECh. 1.1 - Prob. 8WECh. 1.1 - Prob. 9WECh. 1.1 - Prob. 10WECh. 1.2 - Prob. 1CECh. 1.2 - Prob. 2CECh. 1.2 - Prob. 3CECh. 1.2 - Prob. 4CECh. 1.2 - Prob. 5CECh. 1.2 - Prob. 6CECh. 1.2 - Prob. 7CECh. 1.2 - Prob. 8CECh. 1.2 - Prob. 9CECh. 1.2 - Prob. 10CECh. 1.2 - Prob. 11CECh. 1.2 - Prob. 12CECh. 1.2 - Prob. 13CECh. 1.2 - Prob. 14CECh. 1.2 - Prob. 15CECh. 1.2 - Prob. 16CECh. 1.2 - Prob. 17CECh. 1.2 - Prob. 18CECh. 1.2 - Prob. 19CECh. 1.2 - Prob. 20CECh. 1.2 - Prob. 1WECh. 1.2 - Prob. 2WECh. 1.2 - Prob. 3WECh. 1.2 - Prob. 4WECh. 1.2 - Prob. 5WECh. 1.2 - Prob. 6WECh. 1.2 - Prob. 7WECh. 1.2 - Prob. 8WECh. 1.2 - Prob. 9WECh. 1.2 - Prob. 10WECh. 1.2 - Prob. 11WECh. 1.2 - Prob. 12WECh. 1.2 - Prob. 13WECh. 1.2 - Prob. 14WECh. 1.2 - Prob. 15WECh. 1.2 - Prob. 16WECh. 1.2 - Prob. 17WECh. 1.2 - Prob. 18WECh. 1.2 - Prob. 19WECh. 1.2 - Prob. 20WECh. 1.2 - Prob. 21WECh. 1.2 - Prob. 22WECh. 1.2 - Prob. 23WECh. 1.2 - Prob. 24WECh. 1.2 - Prob. 25WECh. 1.2 - Prob. 26WECh. 1.2 - Prob. 27WECh. 1.2 - Prob. 28WECh. 1.2 - Prob. 29WECh. 1.2 - Prob. 30WECh. 1.2 - Prob. 31WECh. 1.2 - Prob. 32WECh. 1.2 - Prob. 33WECh. 1.2 - Prob. 34WECh. 1.2 - Prob. 35WECh. 1.2 - Prob. 36WECh. 1.2 - Prob. 1ST1Ch. 1.2 - Prob. 2ST1Ch. 1.2 - Prob. 3ST1Ch. 1.2 - Prob. 4ST1Ch. 1.2 - Prob. 5ST1Ch. 1.2 - Prob. 6ST1Ch. 1.2 - Prob. 7ST1Ch. 1.2 - Prob. 1ARCh. 1.2 - Prob. 2ARCh. 1.2 - Prob. 3ARCh. 1.2 - Prob. 4ARCh. 1.2 - Prob. 5ARCh. 1.2 - Prob. 6ARCh. 1.2 - Prob. 7ARCh. 1.2 - Prob. 8ARCh. 1.2 - Prob. 9ARCh. 1.2 - Prob. 10ARCh. 1.2 - Prob. 11ARCh. 1.2 - Prob. 12ARCh. 1.2 - Prob. 13ARCh. 1.2 - Prob. 14ARCh. 1.2 - Prob. 15ARCh. 1.2 - Prob. 16ARCh. 1.2 - Prob. 17ARCh. 1.2 - Prob. 18ARCh. 1.2 - Prob. 19ARCh. 1.2 - Prob. 20ARCh. 1.2 - Prob. 21ARCh. 1.2 - Prob. 22ARCh. 1.2 - Prob. 23ARCh. 1.2 - Prob. 24ARCh. 1.2 - Prob. 25ARCh. 1.2 - Prob. 26ARCh. 1.2 - Prob. 27ARCh. 1.2 - Prob. 28ARCh. 1.2 - Prob. 29ARCh. 1.2 - Prob. 30ARCh. 1.2 - Prob. 31ARCh. 1.2 - Prob. 32ARCh. 1.2 - Prob. 33ARCh. 1.2 - Prob. 34ARCh. 1.2 - Prob. 35ARCh. 1.2 - Prob. 36ARCh. 1.2 - Prob. 37ARCh. 1.2 - Prob. 38ARCh. 1.2 - Prob. 39ARCh. 1.2 - Prob. 40ARCh. 1.2 - Prob. 41ARCh. 1.2 - Prob. 42ARCh. 1.2 - Prob. 43ARCh. 1.2 - Prob. 44ARCh. 1.2 - Prob. 45ARCh. 1.2 - Prob. 46ARCh. 1.3 - Prob. 1CECh. 1.3 - Prob. 2CECh. 1.3 - Prob. 3CECh. 1.3 - Prob. 4CECh. 1.3 - Prob. 5CECh. 1.3 - Prob. 6CECh. 1.3 - Prob. 7CECh. 1.3 - Prob. 8CECh. 1.3 - Prob. 9CECh. 1.3 - Prob. 10CECh. 1.3 - Prob. 11CECh. 1.3 - Prob. 12CECh. 1.3 - Prob. 13CECh. 1.3 - Prob. 14CECh. 1.3 - Prob. 15CECh. 1.3 - Prob. 16CECh. 1.3 - Prob. 17CECh. 1.3 - Prob. 18CECh. 1.3 - Prob. 19CECh. 1.3 - Prob. 20CECh. 1.3 - Prob. 21CECh. 1.3 - Prob. 22CECh. 1.3 - Prob. 23CECh. 1.3 - Prob. 24CECh. 1.3 - Prob. 25CECh. 1.3 - Prob. 26CECh. 1.3 - Prob. 1WECh. 1.3 - Prob. 2WECh. 1.3 - Prob. 3WECh. 1.3 - Prob. 4WECh. 1.3 - Prob. 5WECh. 1.3 - Prob. 6WECh. 1.3 - Prob. 7WECh. 1.3 - Prob. 8WECh. 1.3 - Prob. 9WECh. 1.3 - Prob. 10WECh. 1.3 - Prob. 11WECh. 1.3 - Prob. 12WECh. 1.3 - Prob. 13WECh. 1.3 - Prob. 14WECh. 1.3 - Prob. 15WECh. 1.3 - Prob. 16WECh. 1.3 - Prob. 17WECh. 1.3 - Prob. 18WECh. 1.3 - Prob. 19WECh. 1.3 - Prob. 20WECh. 1.3 - Prob. 21WECh. 1.3 - Prob. 22WECh. 1.3 - Prob. 23WECh. 1.3 - Prob. 24WECh. 1.3 - Prob. 25WECh. 1.3 - Prob. 26WECh. 1.3 - Prob. 27WECh. 1.3 - Prob. 28WECh. 1.3 - Prob. 29WECh. 1.3 - Prob. 30WECh. 1.3 - Prob. 31WECh. 1.3 - Prob. 32WECh. 1.3 - Prob. 33WECh. 1.3 - Prob. 34WECh. 1.3 - Prob. 35WECh. 1.3 - Prob. 36WECh. 1.3 - Prob. 37WECh. 1.3 - Prob. 38WECh. 1.3 - Prob. 39WECh. 1.3 - Prob. 40WECh. 1.3 - Prob. 41WECh. 1.3 - Prob. 42WECh. 1.3 - Prob. 43WECh. 1.3 - Prob. 44WECh. 1.3 - Prob. 45WECh. 1.3 - Prob. 46WECh. 1.3 - Prob. 47WECh. 1.3 - Prob. 48WECh. 1.4 - Prob. 1CECh. 1.4 - Prob. 2CECh. 1.4 - Prob. 3CECh. 1.4 - Prob. 4CECh. 1.4 - Prob. 5CECh. 1.4 - Prob. 6CECh. 1.4 - Prob. 7CECh. 1.4 - Prob. 8CECh. 1.4 - Prob. 9CECh. 1.4 - Prob. 10CECh. 1.4 - Prob. 11CECh. 1.4 - Prob. 12CECh. 1.4 - Prob. 13CECh. 1.4 - Prob. 14CECh. 1.4 - Prob. 15CECh. 1.4 - Prob. 16CECh. 1.4 - Prob. 17CECh. 1.4 - Prob. 18CECh. 1.4 - Prob. 19CECh. 1.4 - Prob. 20CECh. 1.4 - Prob. 21CECh. 1.4 - Prob. 22CECh. 1.4 - Prob. 23CECh. 1.4 - Prob. 24CECh. 1.4 - Prob. 25CECh. 1.4 - Prob. 26CECh. 1.4 - Prob. 27CECh. 1.4 - Prob. 28CECh. 1.4 - Prob. 29CECh. 1.4 - Prob. 30CECh. 1.4 - Prob. 31CECh. 1.4 - Prob. 32CECh. 1.4 - Prob. 33CECh. 1.4 - Prob. 34CECh. 1.4 - Prob. 35CECh. 1.4 - Prob. 36CECh. 1.4 - Prob. 37CECh. 1.4 - Prob. 38CECh. 1.4 - Prob. 1WECh. 1.4 - Prob. 2WECh. 1.4 - Prob. 3WECh. 1.4 - Prob. 4WECh. 1.4 - Prob. 5WECh. 1.4 - Prob. 6WECh. 1.4 - Prob. 7WECh. 1.4 - Prob. 8WECh. 1.4 - Prob. 9WECh. 1.4 - Prob. 10WECh. 1.4 - Prob. 11WECh. 1.4 - Prob. 12WECh. 1.4 - Prob. 13WECh. 1.4 - Prob. 14WECh. 1.4 - Prob. 15WECh. 1.4 - Prob. 16WECh. 1.4 - Prob. 17WECh. 1.4 - Prob. 18WECh. 1.4 - Prob. 19WECh. 1.4 - Prob. 20WECh. 1.4 - Prob. 21WECh. 1.4 - Prob. 22WECh. 1.4 - Prob. 23WECh. 1.4 - Prob. 24WECh. 1.4 - Prob. 25WECh. 1.4 - Prob. 26WECh. 1.4 - Prob. 27WECh. 1.4 - Prob. 28WECh. 1.4 - Prob. 29WECh. 1.4 - Prob. 30WECh. 1.4 - Prob. 31WECh. 1.4 - Prob. 32WECh. 1.4 - Prob. 33WECh. 1.4 - Prob. 34WECh. 1.4 - Prob. 35WECh. 1.4 - Prob. 36WECh. 1.5 - Prob. 1CECh. 1.5 - Prob. 2CECh. 1.5 - Prob. 3CECh. 1.5 - Prob. 4CECh. 1.5 - Prob. 5CECh. 1.5 - Prob. 6CECh. 1.5 - Prob. 7CECh. 1.5 - Prob. 8CECh. 1.5 - Prob. 9CECh. 1.5 - Prob. 10CECh. 1.5 - Prob. 11CECh. 1.5 - Prob. 12CECh. 1.5 - Prob. 13CECh. 1.5 - Prob. 14CECh. 1.5 - Prob. 15CECh. 1.5 - Prob. 16CECh. 1.5 - Prob. 1WECh. 1.5 - Prob. 2WECh. 1.5 - Prob. 3WECh. 1.5 - Prob. 4WECh. 1.5 - Prob. 5WECh. 1.5 - Prob. 6WECh. 1.5 - Prob. 7WECh. 1.5 - Prob. 8WECh. 1.5 - Prob. 9WECh. 1.5 - Prob. 10WECh. 1.5 - Prob. 11WECh. 1.5 - Prob. 12WECh. 1.5 - Prob. 13WECh. 1.5 - Prob. 14WECh. 1.5 - Prob. 15WECh. 1.5 - Prob. 16WECh. 1.5 - Prob. 17WECh. 1.5 - Prob. 18WECh. 1.5 - Prob. 19WECh. 1.5 - Prob. 20WECh. 1.5 - Prob. 1ECh. 1.5 - Prob. 2ECh. 1.5 - Prob. 3ECh. 1.5 - Prob. 4ECh. 1.5 - Prob. 5ECh. 1.5 - Prob. 6ECh. 1.5 - Prob. 1ST2Ch. 1.5 - Prob. 2ST2Ch. 1.5 - Prob. 3ST2Ch. 1.5 - Prob. 4ST2Ch. 1.5 - Prob. 5ST2Ch. 1.5 - Prob. 6ST2Ch. 1.5 - Prob. 7ST2Ch. 1.5 - Prob. 8ST2Ch. 1.5 - Prob. 9ST2Ch. 1.5 - Prob. 10ST2Ch. 1.5 - Prob. 11ST2Ch. 1.5 - Prob. 12ST2Ch. 1 - Prob. 1CRCh. 1 - Prob. 2CRCh. 1 - Prob. 3CRCh. 1 - Prob. 4CRCh. 1 - Prob. 5CRCh. 1 - Prob. 6CRCh. 1 - Prob. 7CRCh. 1 - Prob. 8CRCh. 1 - Prob. 9CRCh. 1 - Prob. 10CRCh. 1 - Prob. 11CRCh. 1 - Prob. 12CRCh. 1 - Prob. 13CRCh. 1 - Prob. 14CRCh. 1 - Prob. 15CRCh. 1 - Prob. 16CRCh. 1 - Prob. 17CRCh. 1 - Prob. 18CRCh. 1 - Prob. 19CRCh. 1 - Prob. 20CRCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CTCh. 1 - Prob. 21CTCh. 1 - Prob. 22CTCh. 1 - Prob. 23CTCh. 1 - Prob. 24CT

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