ORGANIC CHEMISTRY-WILEYPLUS NEXTGEN
4th Edition
ISBN: 9781119760924
Author: Klein
Publisher: WILEY
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Chapter 12, Problem 50PP
Interpretation Introduction
Interpretation: The
Concept introduction: Oxidation takes place because of the removal of electrons whereas reduction takes place as a result of the addition of electrons. The oxidized component becomes positively charged and the reduced component becomes negatively charged.
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Using Zaitsev's rule, choose the most stable alkene among the following.
Draw out the structures of each of the options then select the correct answer.
Recall that Zaitsev's Rule is about alkene stability. The trend for this is similar to the
trend for carbocation stability. Either more or fewer groups on the alkene (and the
carbocation) make it more stable. This question is wanting you to remember if it's
more or fewer.
A) 1,2-dimethylcyclohexene
B) 1,6-dimethylcyclohexene
C)
cis-3,4-dimethylcyclohexene
D) They are all of equal stability according to Zaitsev's rule.
Provide the major dehydration product of the following reaction.
Recall which of the four substitution and elimination reactions a dehydration is.
Before you do your S# or EF mechanism, remember what heteroatoms do in the
presence of an acid (aka-the-OH is a bad leaving group, but protonating it might
turn it into a good one).
Don't forget to apply the concept from the previous question.
OH
Ht
A
In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change for
the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct.
H2SO4, H2O
H9SO4
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne
has been oxidized.
The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne
has been reduced.
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne does
not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
The first carbon…
When you react ammonia with a halogenated alkane, will you get only one organic product? Why or why not? (I am not concerned or talking about inorganic products.)
Chapter 12 Solutions
ORGANIC CHEMISTRY-WILEYPLUS NEXTGEN
Ch. 12.1 - Prob. 1LTSCh. 12.1 - Prob. 1PTSCh. 12.1 - Prob. 2ATSCh. 12.1 - Prob. 3CCCh. 12.2 - Prob. 4CCCh. 12.3 - Prob. 8CCCh. 12.3 - Prob. 9CCCh. 12.4 - Prob. 3LTSCh. 12.4 - Prob. 10PTSCh. 12.4 - Prob. 11ATS
Ch. 12.4 - Prob. 4LTSCh. 12.4 - Prob. 12PTSCh. 12.4 - Prob. 13ATSCh. 12.6 - Prob. 14CCCh. 12.6 - Prob. 5LTSCh. 12.6 - Prob. 15PTSCh. 12.6 - Prob. 16PTSCh. 12.7 - Prob. 18CCCh. 12.9 - Prob. 6LTSCh. 12.9 - Prob. 19PTSCh. 12.9 - Prob. 20ATSCh. 12.9 - Prob. 21CCCh. 12.10 - Prob. 7LTSCh. 12.10 - Prob. 22PTSCh. 12.10 - Prob. 23ATSCh. 12.13 - Prob. 8LTSCh. 12.13 - Prob. 24PTSCh. 12.13 - Prob. 25ATSCh. 12.13 - Prob. 26CCCh. 12.13 - Prob. 9LTSCh. 12.13 - Prob. 27PTSCh. 12.13 - Prob. 28ATSCh. 12 - Prob. 29PPCh. 12 - Prob. 30PPCh. 12 - Prob. 31PPCh. 12 - Prob. 32PPCh. 12 - Prob. 33PPCh. 12 - Prob. 34PPCh. 12 - Prob. 35PPCh. 12 - Prob. 36PPCh. 12 - Prob. 37PPCh. 12 - Prob. 38PPCh. 12 - Prob. 39PPCh. 12 - Prob. 40PPCh. 12 - Prob. 41PPCh. 12 - Prob. 42PPCh. 12 - Prob. 43PPCh. 12 - Prob. 44PPCh. 12 - Prob. 45PPCh. 12 - Prob. 46PPCh. 12 - Prob. 47PPCh. 12 - Prob. 48PPCh. 12 - Prob. 49PPCh. 12 - Prob. 50PPCh. 12 - Prob. 51PPCh. 12 - Prob. 52PPCh. 12 - Prob. 53ASPCh. 12 - Prob. 54ASPCh. 12 - Prob. 55ASPCh. 12 - Prob. 62IPCh. 12 - Prob. 64IPCh. 12 - Prob. 65IPCh. 12 - Prob. 66IPCh. 12 - Prob. 67IPCh. 12 - Prob. 68IPCh. 12 - Prob. 69IPCh. 12 - Prob. 74IP
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