Chapter 12.5, Problem 10MCQ

To determine

To find: The minimum, first quartile, median, third quartile, and maximum of each data set.

Answer to Problem 10MCQ

The minimum first quartile is $30.5$ , median is $90$ , third quartile is $102.5$ , and maximum is $112$ .

Explanation of Solution

Given information:

The given daily visitors are $34293225979311210890$ .

Calculation:

Consider the daily visitors.

Minimum: the least number in data set is called the minimum

Minimum $=25$

Maximum: the greatest number in data set is called maximum.

Maximum $=112$

Median: the median value is $90$

First quartile: the data set is divided into four equal part then the first quartile is the median of the lower half is represented by $Q_1$

  $\begin{array}{c}{Q}_1=\frac{29+32}{2}\\ =30.5\end{array}$

Third quartile: the third quartile is the median of the upper half is represented by $Q_3$

  $\begin{array}{c}{Q}_3=\frac{97+108}{2}\\ =102.5\end{array}$

The box and whisker plot as shown in the figure (1)

  

Figure (1)

Therefore, the minimum, first quartile $30.5$ , median $90$ , third quartile $102.5$, and maximum $112$