Concept explainers
How would each of the following pairs of compounds differ in their IR spectra?
a. d.
b. e.
c. f.
(a)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
The IR spectrum of cyclopentene is different from pentyne because the absorption of
Explanation of Solution
The given compounds are cyclopentene and pentyne as shown below.
Figure 1
Cyclopentene contains
The IR spectrum of cyclopentene is different from pentyne because the absorption of
(b)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
The IR absorption of propanoic acid is different from methyl acetate due to broad peak of
Explanation of Solution
The given compounds are propanoic acid and methyl acetate as shown below.
Figure 2
Propanoic acid contains
The IR absorptions of propanoic acid is different from methyl acetate due to broad peak of
(c)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
The IR absorptions of butan-
Explanation of Solution
The given compounds are butan-
Figure 3
Butan-
The IR absorptions of propanoic acid is different from methyl acetate due to broad peak of
(d)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
The IR spectra of methyl hexanoate are different from
Explanation of Solution
The given compound are
Figure 4
Methyl hexanoate contains
The IR spectra of methylhexanoate is different from
(e)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
But-
Explanation of Solution
But-
But-
(f)
Interpretation: The given pair of compounds is to be differentiated on the basis of their IR spectra.
Concept introduction: IR spectroscopy is used to identify the functional group present in a compound. Each and every bond vibrates at a characteristic frequency.
Answer to Problem 13.40P
The IR spectra of N, N-diethylprop-
Explanation of Solution
The given compound are N, N-diethylprop-
The IR spectra of N, N-diethylprop-
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Chapter 13 Solutions
Organic Chemistry -Study Guide / Solution Manual (Custom)
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- How could IR spectroscopy distinguish between 1,5-hexadiene and 2,4-hexadiene?arrow_forwardTHIS CAN NOT BE HAND - DRAWN Illustrate using a computer program the molecule from the molecular formula and interpret each of the following 1H NMR spectra. The integration for each peak is given above the peak. All spectra were taken from http://riodb01.ibase.aist.go.jp/sdbs/cgi-bin/direct_frame_top.cgi.arrow_forward
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