ORGANIC CHEMISTRY- NEXTGEN PACKAGE
ORGANIC CHEMISTRY- NEXTGEN PACKAGE
4th Edition
ISBN: 9781119863908
Author: Klein
Publisher: WILEY
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Chapter 13, Problem 47ASP
Interpretation Introduction

Interpretation: The possible intermediate formed in the given reaction needs to be identified.

Concept Introduction:

Epoxide reaction with alcohol under acidic conditions results in ring opening. It is an acid-catalyzed ring opening reaction. Alcohol act as a nucleophile in this case. Under acidic condition, first epoxide gets protonated and this protonated epoxide then reacts with alcohol to cause ring opening.

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For the given Sy2 reaction, draw the organic and inorganic products of the reaction, and identify the nucleophile, substrate, and leaving group. Include wedge-and-dash bonds and draw hydrogen on a stereocenter. :CEN Organic product Inorganic product + Draw the organic product. Draw the inorganic product. Incorrect
Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…
By analyzing the starting material and the product, the following reaction is possibly an example of what type of mechanism(s)?
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