Chapter 13, Problem 96A

(a)

Interpretation Introduction

Interpretation: The given reaction between vanadium pentoxide and hydrogen is to be balanced.

Concept introduction:

A chemical reaction is balanced if both sides of compounds possess an equal number of atoms and the total charge for each component of the reaction.

Answer to Problem 96A

  ${\text{2V}}_{\text{2}}{\text{O}}_{\text{5}}+4{\text{H}}_{\text{2}}\to 2{\text{V}}_{\text{2}}{\text{O}}_{\text{3}}+4{\text{H}}_{\text{2}}\text{O}$

Explanation of Solution

The given reaction is as follows:

  ${\text{V}}_{\text{2}}{\text{O}}_{\text{5}}+{\text{H}}_{\text{2}}\to {\text{V}}_{\text{2}}{\text{O}}_{\text{3}}+{\text{H}}_{\text{2}}\text{O}$

Multiply ${\text{V}}_{\text{2}}{\text{O}}_{\text{5}}$ and ${\text{V}}_{\text{2}}{\text{O}}_{\text{3}}$ by 2 on each side.

  ${\text{2V}}_{\text{2}}{\text{O}}_{\text{5}}+{\text{H}}_{\text{2}}\to 2{\text{V}}_{\text{2}}{\text{O}}_{\text{3}}+{\text{H}}_{\text{2}}\text{O}$

Now, multiply water and by 4 to balance O and H atoms:

  ${\text{2V}}_{\text{2}}{\text{O}}_{\text{5}}+4{\text{H}}_{\text{2}}\to 2{\text{V}}_{\text{2}}{\text{O}}_{\text{3}}+4{\text{H}}_{\text{2}}\text{O}$

Now, the above reaction is balanced.

(b)

Interpretation Introduction

Interpretation: The given reaction is to be balanced.

Concept introduction:

A chemical reaction is balanced if both sides of compounds possess an equal number of atoms and the total charge for each component of the reaction.

Answer to Problem 96A

  ${\left({\text{NH}}_{\text{4}}\right)}_2{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}\to {\text{Cr}}_{\text{2}}{\text{O}}_{\text{3}}+{\text{N}}_{\text{2}}+4{\text{H}}_{\text{2}}\text{O}$

Explanation of Solution

The given reaction is as follows:

  ${\left({\text{NH}}_{\text{4}}\right)}_2{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}\to {\text{Cr}}_{\text{2}}{\text{O}}_{\text{3}}+{\text{N}}_{\text{2}}+{\text{H}}_{\text{2}}\text{O}$

All atoms are balanced except H and O. Multiply water on the product side by 4.

  ${\left({\text{NH}}_{\text{4}}\right)}_2{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}\to {\text{Cr}}_{\text{2}}{\text{O}}_{\text{3}}+{\text{N}}_{\text{2}}+4{\text{H}}_{\text{2}}\text{O}$

Now, the above reaction is balanced.