Introductory Statistics (10th Edition)
10th Edition
ISBN: 9780321989178
Author: Neil A. Weiss
Publisher: PEARSON
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Chapter 13.2, Problem 12E
To determine
To decide: Whether assumptions 1 and 2 to use the test are satisfied.
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.A sample of 9 measurements, randomly selected from a normally distributed population,
resulted in x= 2.6, and s= 0.9 Conduct a hypothesis test to verify the claim that the
population mean is greater than 2.5 . Use a=.05
Consider the following hypothesis test :
H0:μ =12.5
Ha:μ ‡12.5
**THAT A sample of size 18 provided a sample mean (12.9) and sample standard deviation is (0.8).
a-Compute the test statistic.
b-Determine the range of p-value from the table of t-distribution? What is the rejection rule ?
and what is your conclusion at α=0.01?
c-What is the rejection rule ,using critical vale approach? What is your conclusion at α=0.05?
Q1/ Consider the following hypothesis test :
H0:μ 65
Ha:μ 65
A sample of size 15 provided a sample mean (63) and population standard deviation is (2).
a-Compute the test statistic.
b-Compute p-value from the table? What is the rejection rule ?
and what is your conclusion at α=0.05?
c-What is the rejection rule ,using critical vale approach? What is your conclusion at α=0.05?
..............................................................................................................................
Q2/ Consider the following hypothesis test :
H0:μ =12.5
Ha:μ ‡12.5
A sample of size 18 provided a sample mean (12.9) and sample standard deviation is (0.8).
a-Compute the test statistic.
b-Determine the range of p-value from the table of t-distribution? What is the rejection rule ?
Chapter 13 Solutions
Introductory Statistics (10th Edition)
Ch. 13.1 - What is meant by saying that a variable has a...Ch. 13.1 - How do you identify different chi-square...Ch. 13.1 - Prob. 3ECh. 13.1 - The t-table has entries for areas of 0.10, 0.05,...Ch. 13.1 - Prob. 5ECh. 13.1 - In Exercises 13.5-13.8, use Table VII to find the...Ch. 13.1 - Prob. 7ECh. 13.1 - Prob. 8ECh. 13.2 - Why is the phrase goodness of fit used to describe...Ch. 13.2 - Prob. 10E
Ch. 13.2 - Prob. 11ECh. 13.2 - Prob. 12ECh. 13.2 - Prob. 13ECh. 13.2 - Prob. 14ECh. 13.2 - Prob. 15ECh. 13.2 - Prob. 16ECh. 13.2 - Prob. 17ECh. 13.2 - In each of Exercises 13.1813.23, we have provided...Ch. 13.2 - In each of Exercises 13.1813.23, we have provided...Ch. 13.2 - Prob. 20ECh. 13.2 - Prob. 21ECh. 13.2 - Prob. 22ECh. 13.2 - In each of Exercises 13.18-13.23, we have provided...Ch. 13.2 - In each of Exercises 13.24-13.33, apply the...Ch. 13.2 - In each of Exercises 13.24-13.3, apply the...Ch. 13.2 - In each of Exercises 13.24-13.33, apply the...Ch. 13.2 - Prob. 27ECh. 13.2 - In Each of Exercises 13.24-13.33, apply the...Ch. 13.2 - Prob. 29ECh. 13.2 - In each of Exercises 13.24-13.33, apply the...Ch. 13.2 - Prob. 31ECh. 13.2 - In each of Exercises 13.24-13.33, apply the...Ch. 13.2 - Prob. 33ECh. 13.2 - Prob. 34ECh. 13.2 - The chi-square goodness-of-fit test provides a...Ch. 13.3 - Identify the type of table that is used to group...Ch. 13.3 - What are the small boxes inside the heavy lines of...Ch. 13.3 - Suppose that bivariate data are to be grouped into...Ch. 13.3 - Identify three ways in which the total number of...Ch. 13.3 - Presidential Election. According to Dave Leip's...Ch. 13.3 - Prob. 41ECh. 13.3 - Prob. 42ECh. 13.3 - Prob. 43ECh. 13.3 - Prob. 44ECh. 13.3 - Prob. 45ECh. 13.3 - Prob. 46ECh. 13.3 - AIDS Cases. According to the Centers for Disease...Ch. 13.3 - Prob. 48ECh. 13.3 - Prob. 49ECh. 13.3 - Prob. 50ECh. 13.3 - Farms. The U.S. Department of Agriculture...Ch. 13.3 - Prob. 52ECh. 13.3 - AIDS Cases. Refer to Exercise 13.47. For AIDS case...Ch. 13.3 - Prob. 54ECh. 13.3 - Prob. 55ECh. 13.3 - Prob. 56ECh. 13.3 - In each of Exercises 13.57-13.59, use the...Ch. 13.3 - In each of Exercises 13.57-13.59, use the...Ch. 13.3 - In each of Exercises 13.57-13.59, use the...Ch. 13.3 - In the exercise, you are to consider two variables...Ch. 13.3 - Prob. 61ECh. 13.4 - To decide whether two variables of a population...Ch. 13.4 - Prob. 63ECh. 13.4 - Prob. 64ECh. 13.4 - Prob. 65ECh. 13.4 - Prob. 66ECh. 13.4 - Education and Salary. Studies have shown that a...Ch. 13.4 - Identify three techniques that can he tried as a...Ch. 13.4 - Prob. 69ECh. 13.4 - Prob. 70ECh. 13.4 - In each of Exercises 13.69-13.74, we have given...Ch. 13.4 - Prob. 72ECh. 13.4 - In each of Exercises 13.69-13.74, we have given...Ch. 13.4 - Prob. 74ECh. 13.4 - Prob. 75ECh. 13.4 - Prob. 76ECh. 13.4 - Prob. 77ECh. 13.4 - Prob. 78ECh. 13.4 - In Exercises13.79-13.86, use either the...Ch. 13.4 - In Exercises 13.79-13.86, use either the...Ch. 13.4 - Prob. 81ECh. 13.4 - In Exercises 13.7913.86, use either she critical...Ch. 13.4 - In Exercises 13.7913.86, use either she...Ch. 13.4 - Prob. 84ECh. 13.4 - Prob. 85ECh. 13.4 - Prob. 86ECh. 13.4 - Prob. 87ECh. 13.4 - In Exercises 13.7913.86, use either the...Ch. 13.4 - Prob. 89ECh. 13.4 - Prob. 90ECh. 13.4 - Prob. 91ECh. 13.4 - Prob. 92ECh. 13.5 - Prob. 93ECh. 13.5 - For what purpose is a chi-square homogeneity test...Ch. 13.5 - Prob. 95ECh. 13.5 - State the null and alternative hypotheses for a...Ch. 13.5 - Prob. 97ECh. 13.5 - Prob. 98ECh. 13.5 - Prob. 99ECh. 13.5 - A chi-square homogeneity test is to be conducted...Ch. 13.5 - Prob. 101ECh. 13.5 - In Exercises 13.101-13.106, use either the...Ch. 13.5 - In Exercises 13.101-13.106, use either the...Ch. 13.5 - Prob. 104ECh. 13.5 - Prob. 105ECh. 13.5 - Prob. 106ECh. 13.5 - In each of Exercises 13.107 and 13.108 a. use the...Ch. 13.5 - In each of Exercises 13.107 and 13.108, a. use the...Ch. 13 - How do you distinguish among the infinitely many...Ch. 13 - Prob. 2RPCh. 13 - Prob. 3RPCh. 13 - Explain why a chi-square goodness-of-fit test, a...Ch. 13 - Prob. 5RPCh. 13 - Rending the expected-frequency assumptions for a...Ch. 13 - Prob. 7RPCh. 13 - Suppose that you have bivariate data for an entire...Ch. 13 - Suppose that you have bivariate data for a sample...Ch. 13 - Prob. 10RPCh. 13 - Prob. 11RPCh. 13 - Prob. 12RPCh. 13 - Prob. 13RPCh. 13 - Presidents. Refer to Problem 12. a. Find the...Ch. 13 - Prob. 15RPCh. 13 - Prob. 16RPCh. 13 - Prob. 17RPCh. 13 - Prob. 18RPCh. 13 - Prob. 19RPCh. 13 - Income and Residence. The U.S. Census Bureau...Ch. 13 - Economy in Recession? The Quinnipiac University...Ch. 13 - Prob. 22RPCh. 13 - With holding Treatment. Several years ago. a poll...Ch. 13 - Recall from Chapter 1 (see page 34) that the Focus...Ch. 13 - At the beginning of this chapter, we presented a...
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- Q1/Consider the following hypothesis test : H0:μ 65 Ha:μ 65 A sample of size 15 provided a sample mean (63) and population standard deviation is (2). a-Compute the test statistic. b-Compute p-value from the table? What is the rejection rule ? and what is your conclusion at α=0.05? c-What is the rejection rule ,using critical vale approach? What is your conclusion at α=0.05? ........................................................................................................................ Q2 /Consider the following hypothesis test : H0:μ =12.5 Ha:μ ‡12.5 A sample of size 18 provided a sample mean (12.9) and sample standard deviation is (0.8). a-Compute the test statistic. b-Determine the range of p-value from the table of t-distribution? What is the rejection rule ?arrow_forwardassume that you have a sample of n1=9, with the sample mean x1=50, and a sample standard deviation of S1=5, and you have an independent sample of n2=15 from another population with a sample mean of X2=31, and the sample deviation S2=7. Construct a 99% confidence interval estimate of the population mean difference between u1 and u2. Assume that the two population variances are equal.arrow_forwardConsider the following hypothesis test : H0:μ =12.5 Ha:μ ‡12.5 **THAT A sample of size 18 provided a sample mean (12.9) and sample standard deviation is (0.8). *What is the rejection rule ,using critical vale approach? What is your conclusion at α=0.05?arrow_forward
- Also, using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2009 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2009 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?arrow_forwardIn a hypothesis test with hypotheses Ho: μ ≤ 54 and H1: μ > 54, a random sample of 24 elements selected from the population produced a mean of 58.6 and a standard deviation of 13.4. The test is to be made at the 10% significance level. Assume the population is normally distributed. What is the critical value of t ?arrow_forwardWe have given the relative frequencies for the null hypothesis of a chi-square goodness-of-fit test and the sample size. In each case, decide whether Assumptions 1 and 2 for using that test are satisfied. Sample size: n = 50. Relative frequencies: 0.20, 0.20, 0.25, 0.30, 0.05.arrow_forward
- For a random sample of 50 measurements of X1, sample mean x ̄1 = 200, sample standard deviation s1 = 10. For X2, from a random sample of 50, sample mean x ̄2 = 190 and sample standard deviation s2 = 15. Assume that population distributions are approximately independent normal with unequal variances. Answer the following questions 1 through 3. 1. Construct a 90% confidence interval for μ1 − μ2. (i) State the assump- tions, (ii) show your work, and (iii) interpret the result in context of the problem. 2. Using the same samples, you want to test whether the difference between two population means is 5 or not at the significance level α = 0.1. H0 : μ1 − μ2 = 5 vs H1 : μ1 − μ2 ̸= 5. What would your conclusion be? Support your answer briefly. You don’t need to conduct the hypothesis test.arrow_forwardRecently, the annual number of driver deaths per 100,000 for the selected age groups was as follows: Age Number of Driver Deaths per 100,000 16–19 38 20–24 36 25–34 24 35–54 20 55–74 18 75+ 28 Use the 4 steps of hypothesis testing to see if the prediction is significant with a criteria of alpha=.05 on the following data For each age group, pick the midpoint of the interval for the X value. (For the 75+ group, use 80.)arrow_forward
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