Chapter 13.4, Problem 4PPS

To determine

To calculate:

The probability of given event.

Answer to Problem 4PPS

The probability non-strike event is $45\%$ .

Explanation of Solution

Given information:

Event:

Bridget is a member of the bowling club at her school. Last season she belowed a strike $60\%$ of the time.

Calculation:

Suppose, a bowler got a strike $60\%$ of the last time session.

Based on geometric model, let the rolls of a six-sided die simulate the bowlers strikes for the upcoming season. Since the bowler got strikes $60\%$ of the time, then let the numbers $1-3$ on the die represent an $A$ .

Then let the numbers $4$ and $5$ represent a non-strike , and roll again when the number $6$ comes up.

Now roll a die $20$ times, the frequency of outcomes will vary between set of $20$ rolls. One such set of rolls can be recorded table as follows:

Outcome	Frequency
Strike	$11$
Non-Strike	$9$
Total	$20$

Now, divide each frequency in the frequency table to get the probabilities for each outcome.

Outcome	Frequency	Probability
Strike	$11$	$\frac{11}{20}=0.55$
Non-Strike	$9$	$\frac{9}{20}=0.45$
Total	$20$	$\frac{20}{20}=1$

Make a probability histogram by charting probability on the vertical axis and outcomes on the horizontal axis.

  

Hence, therefore that the bowler gets a strike on the bowlers next turn is $55\%$ , and the probability of getting a non-strike is

  $100\%-55\%=45\%$

Therefore, the probability non-strike event is $45\%$ .