Chapter 13.5, Problem 28STP

To determine

To determine probability of given event.

Answer to Problem 28STP

Correct answer is option A.

Explanation of Solution

Probability that she will be in the second P.E. class is,

(Total possibilities are 6)

P(second P.E ) = $\frac{1}{6}$

Probability of the first lunch,

(Total possibilities are 3)

P(first lunch) = $\frac{1}{3}$

As both the events are independent of each other, hence the probability that she will be in the second P.E class and the first lunch is,

  $P=\frac{1}{6}\cdot \frac{1}{3}=\frac{1}{18}$

Option A is correct answer.