Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 14, Problem 14.46AP
Interpretation Introduction
Interpretation:
The structure of compound A is to be stated with the help of given information.
Concept introduction:
Ozonolysis is the oxidative cleavage of the double bond, where
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An optically active alkyne A (C10H14) can be catalytically hydrogenated to butylcyclohexane. Treatment of A with EtMgBr liberates no gas. Catalytic hydrogenation of A over Pd/C in the presence of quinoline poison and treatment of the product with O3 and then H2O2 gives an optically active tricarboxylic acid C8H12O6 (A tricarboxylic acids is a compound with three - CO2H groups.). Give the structure of A, and account for all observations.
4. Compound A has the formula C 8H 8. It reacts rapidly with KMnO 4 to give CO 2 and a carboxylic acid, B (C 7H 6O 2), but reacts with only 1 molar equivalent of H 2 on catalytic hydrogenation over a palladium catalyst. On hydrogenation under conditions that reduce aromatic rings, 4, equivalents of H 2 are taken up and hydrocarbon C (C 8H 16) is produced. What are the structures of A, B, and C.
Nitromethane is reacted with ethyl prop-2-enoate with EtO-Na+, EtOH 3 equivalents to give the product X(C16). X then reacts with H2/Raney Ni to give the product Y(C14), which in turn reacts with Na to give Z (C12). Indicate which products X, Y and Z are.
Chapter 14 Solutions
Organic Chemistry
Ch. 14 - Prob. 14.1PCh. 14 - Prob. 14.2PCh. 14 - Prob. 14.3PCh. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - Prob. 14.9PCh. 14 - Prob. 14.10P
Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26APCh. 14 - Prob. 14.27APCh. 14 - Prob. 14.28APCh. 14 - Prob. 14.29APCh. 14 - Prob. 14.30APCh. 14 - Prob. 14.31APCh. 14 - Prob. 14.32APCh. 14 - Prob. 14.33APCh. 14 - Prob. 14.34APCh. 14 - Prob. 14.35APCh. 14 - Prob. 14.36APCh. 14 - Prob. 14.37APCh. 14 - Prob. 14.38APCh. 14 - Prob. 14.39APCh. 14 - Prob. 14.40APCh. 14 - Prob. 14.41APCh. 14 - Prob. 14.42APCh. 14 - Prob. 14.43APCh. 14 - Prob. 14.44APCh. 14 - Prob. 14.45APCh. 14 - Prob. 14.46APCh. 14 - Prob. 14.47AP
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- An achiral hydrocarbon A of molecular formula C7H12 reacts with two equivalents of H2 in the presence of Pd-C to form CH3CH2CH2CH2CH(CH3)2. One oxidative cleavage product formed by the treatment of A with O3 is CH3COOH. Reaction of A with H2 and Lindlar catalyst forms B, and reaction of A with Na, NH3 forms C. Identify compounds A, B, and C. Be sure to answer all parts.arrow_forward1. write out all the isomers of the compound with molecular formula C4H10O. 2. select the normal/primary isomer and treat it with conc.H2SO4 and heat to produce A. Identify the type of reaction 3. Treatment of A with HCl/H2O gives B and with cold KMnO4/ OH- gives C . Give the name and structures of A, B and C 4. Treatment of A with Hot KMnO4/OH- gives D followed by acidification of the mixture to give E. What is D and E ?arrow_forwardFollowing is a retrosynthetic analysis for the synthesis of the herbicide (S)-Metolachlor from 2-ethyl-6-methylaniline, chloroacetic acid, acetone, and methanol. Show reagents and experimental conditions for the synthesis of Metolachlor from these four organic starting materials. Your synthesis will most likely give a racemic mixture. The chiral catalyst used by Novartis for reduction in Step 2 gives 80% enantiomeric excess of the S enantiomer.arrow_forward
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- An unknown hydrocarbon A with the formula C6H10 reacts with 1 molar equivalent of H2 over a palladium catalyst to give B C6H12 (Rxn 1). Hydrocarbon A also reacts with OsO4 to give the glycol C (Rxn 2). A gives 5-oxohexanal on ozonolysis (Rxn 3). Draw the structures of A, B, and C. Give the reactions.arrow_forwardCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.arrow_forward
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