Chapter 14.15, Problem 14.32P

Interpretation Introduction

Interpretation:

The $\text{pH}$ of $\text{1}\text{.00 L}$ of rain water contain $\text{5}\text{.47mg}$ of ${\text{NO}}_{\text{2}}$ has to be calculated.

Concept Introduction:

$\text{pH}$ is a logarithmic expression to express a solution is acidic, basic or neutral.  The $\text{pH}$ scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature.

$\text{pH + pOH= 14}$

$\text{pH = -log}\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]$

$\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]{\text{= antilog(-pH) =10}}^{\text{-pH}}$