Using K a value of F - , K b value for F - has to be calculated. Concept Introduction: Acid dissociation constant ( K a ) : It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of K b can be calculated by using K a and vice versa. This relation is given as, K b = K w K a or K a = K w K b
Using K a value of F - , K b value for F - has to be calculated. Concept Introduction: Acid dissociation constant ( K a ) : It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of K b can be calculated by using K a and vice versa. This relation is given as, K b = K w K a or K a = K w K b
Solution Summary: The author explains the acid dissociation constant (K_Texta), which is an equilibrium constant that refers to the ionization of an acid.
Using Ka value of F-, Kb value for F- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(b)
Interpretation Introduction
Interpretation:
Using Ka value of OBr-, Kb value for OBr- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(c)
Interpretation Introduction
Interpretation:
Using Ka value of HS-, Kb value for HS- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(d)
Interpretation Introduction
Interpretation:
Using Ka value of S2-, Kb value for S2- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Rank the following acids in order of increasing strength: ClCH2SH, CH3SH, H2S.
The hypochlorite ion, ClO-, acts as a weak base. (a) Is ClO-stronger or weaker base than hydroxylamine? (b) WhenClO- acts as a base, which atom, Cl or O, acts as the protonacceptor? (c) Can you use formal charges to rationalize youranswer to part (b)?
For 1.15×10−2 M Ba(OH)2, determine [OH−] and [H3O+]
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