Concept explainers
(a)
Interpretation:
The
Concept Introduction:
(b)
Interpretation:
The required volume of
Concept Introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction.
Equivalence point:
The point, where the amount of base added completely neutralizes the taken amount of acid in the titration is known as equivalence point.
(c)
Interpretation:
Concept Introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction.
Equivalence point:
The point, where the amount of base added completely neutralizes the taken amount of acid in the titration is known as equivalence point.
The negative log of base 10
(d)
Interpretation:
Exact
Concept Introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction.
Equivalence point:
The point, where the amount of base added to completely neutralize the taken amount of acid in the titration is known as equivalence point.
The negative log of base 10
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General Chemistry: Atoms First
- Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a) before any NaOH is added? (b) at half-neutralization? (c) at the equivalence point? (d) when 0.10 mL less than the volume of NaOH to reach the equivalence point is added? (e) when 0.10 mL more than the volume of NaOH to reach the equivalence point is added? (f) Use your data to construct a plot similar to that shown in Figure 14.10 (pH versus volume NaOH added).arrow_forwardCalculate the pH change when 10.0 mL of 0.100-M NaOH is added to 90.0 mL pure water, and compare the pH change with that when the same amount of NaOH solution is added to 90.0 mL of a buffer consisting of 1.00-M NH3 and 1.00-M NH4Cl. Assume that the volumes are additive. Kb of NH3 = 1.8 × 10-5.arrow_forwardFor the titration of 50.0 mL of 0.150 M ethylamine. C2H5NH2, with 0.100 M HCl, find the pH at each of the following points, and then use that information to sketch the titration curve and decide on an appropriate indicator. (a) At the beginning, before HCl is added (b) At the halfway point in the titration (c) When 75% of the required acid has been added (d) At the equivalence point (e) When 10.0 mL more HCl has been added than is required (f) Sketch the titration curve. (g) Suggest an appropriate indicator for this titration.arrow_forward
- Two acids, each approximately 0.01 M in concentration, are titrated separately with a strong base. The adds show the following pH values at the equivalence point: HA, pH = 9.5, and HB, pH = 8.5. (a) Which is the stronger acid, HA or HB? (b) Which of the conjugate bases, A or B, is the stronger base?arrow_forwardWhen 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence point is reached when 35.00 mL base has been added. After 20.00 mL NaOH solution has been added, the titration mixture has a pH of 5.75. Calculate the ionization constant of the acid.arrow_forwardGiven three acid-base indicators—methyl orange (end point at pH 4), bromthymol blue (end point at pH 7), and phenolphthalein (end point at pH 9)—which would you select for the following acid-base titrations? (a) perchloric acid with an aqueous solution of ammonia (b) nitrous acid with lithium hydroxide (c) hydrobromic acid with strontium hydroxide (d) sodium fluoride with nitric acidarrow_forward
- A solution is prepared by dissolving 0.350 g of benzoic acid, HC7H5O2, in water to make 100.0 mL of solution. A 30.00-mL sample of the solution is titrated with 0.272 M KOH. Calculate the pH of the solution (a) before titration. (b) halfway to the equivalence point. (c) at the equivalence point.arrow_forwardA buffer is prepared by mixing 525 mL of 0.50 M formic acid, HCHO2, and 475 mL of 0.50 M sodium formate, NaCHO2. Calculate the pH. What would be the pH of 85 mL of the buffer to which 8.6 mL of 0.15 M hydrochloric acid had been added?arrow_forwardSketch two pH curves, one for the titration of a weak acid with a strong base and one for a strong acid with a strong base. How are they similar? How are they different? Account for the similarities and the differences.arrow_forward
- Consider the following four titrations. i. 100.0 mL of 0.10 M HCl titrated by 0.10 M NaOH ii. 100.0 mL of 0.10 M NaOH titrated by 0.10 M HCl iii. 100.0 mL of 0.10 M CH3NH2 titrated by 0.10 M HCl iv. 100.0 mL of 0.10 M HF titrated by 0.10 M NaOH Rank the titrations in order of: a. increasing volume of titrant added to reach the equivalence point. b. increasing pH initially before any titrant has been added. c. increasing pH at the halfway point in equivalence. d. increasing pH at the equivalence point. How would the rankings change if C5H5N replaced CH3NH2 and if HOC6H5 replaced HF?arrow_forwardAn acid-base titration was used to find the percentage of NaHCO3 in 0.310 g of a powdered commercial product used to relieve upset stomachs. The titration required 14.3 mL of 0.101-M HCl to titrate the powder to the equivalence point. Assume that the NaHCO3 in the powder is the only substance that reacted with the titrant. Calculate the percentage of NaHCO3 in the powder.arrow_forward
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