Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 15, Problem 31AP
An object of mass m moves in
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Physics for Scientists and Engineers with Modern Physics
Ch. 15.1 - A block on the end of a spring is pulled to...Ch. 15.2 - Consider a graphical representation (Fig. 15.3) of...Ch. 15.2 - shows two curves representing particles undergoing...Ch. 15.2 - An object of mass m is hung from a spring and set...Ch. 15.4 - The ball in Figure 15.13 moves in a circle of...Ch. 15.5 - The grandfather clock in the opening storyline...Ch. 15 - A 0.60-kg block attached to a spring with force...Ch. 15 - A piston in a gasoline engine is in simple...Ch. 15 - The position of a particle is given by the...Ch. 15 - Prob. 4P
Ch. 15 - Review. A particle moves along the x axis. It is...Ch. 15 - Prob. 6PCh. 15 - A particle moving along the x axis in simple...Ch. 15 - The initial position, velocity, and acceleration...Ch. 15 - You attach an object to the bottom end of a...Ch. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12PCh. 15 - A simple harmonic oscillator of amplitude A has a...Ch. 15 - Review. A 65.0-kg bungee jumper steps off a bridge...Ch. 15 - Review. A 0.250-kg block resting on a...Ch. 15 - While driving behind a car traveling at 3.00 m/s,...Ch. 15 - A simple pendulum makes 120 complete oscillations...Ch. 15 - A particle of mass m slides without friction...Ch. 15 - A physical pendulum in the form of a planar object...Ch. 15 - Prob. 20PCh. 15 - Prob. 21PCh. 15 - Consider the physical pendulum of Figure 15.16....Ch. 15 - A watch balance wheel (Fig. P15.25) has a period...Ch. 15 - Show that the time rate of change of mechanical...Ch. 15 - Show that Equation 15.32 is a solution of Equation...Ch. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Considering an undamped, forced oscillator (b =...Ch. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - An object of mass m moves in simple harmonic...Ch. 15 - Prob. 32APCh. 15 - An object attached to a spring vibrates with...Ch. 15 - Prob. 34APCh. 15 - A pendulum of length L and mass M has a spring of...Ch. 15 - Prob. 36APCh. 15 - Review. A particle of mass 4.00 kg is attached to...Ch. 15 - Prob. 38APCh. 15 - Prob. 39APCh. 15 - Prob. 40APCh. 15 - Review. A lobstermans buoy is a solid wooden...Ch. 15 - Prob. 42APCh. 15 - Prob. 43APCh. 15 - Prob. 44APCh. 15 - A block of mass m is connected to two springs of...Ch. 15 - Review. A light balloon filled with helium of...Ch. 15 - A particle with a mass of 0.500 kg is attached to...Ch. 15 - A smaller disk of radius r and mass m is attached...Ch. 15 - Prob. 49CPCh. 15 - Prob. 50CPCh. 15 - A light, cubical container of volume a3 is...
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- A simple harmonic oscillator has amplitude A and period T. Find the minimum time required for its position to change from x = A to x = A/2 in terms of the period T.arrow_forwardIn an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.arrow_forwardIf the amplitude of a damped oscillator decreases to 1/e of its initial value after n periods, show that the frequency of the oscillator must be approximately [1 − (8π2n2)−1] times the frequency of the corresponding undamped oscillator.arrow_forward
- A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy of the system is 2.00 J. Find (a) the force constant of the spring and (b) the amplitude of the motion.arrow_forwardThe total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the kinetic energy of the system when the position of the oscillator is 0.750 cm? b. What is the potential energy of the system at this position? c. What is the position for which the potential energy of the system is equal to its kinetic energy? d. For a simple harmonic oscillator, what, if any, are the positions for which the kinetic energy of the system exceeds the maximum potential energy of the system? Explain your answer. FIGURE P16.73arrow_forwardAn object of mass m moves in simple harmonic motion with amplitude 12.0 cm on a light spring. Its maximum acceleration is 108 cm/s2. Regard m as a variable. (a) Find the period T of the object. (b) Find its frequency f. (c) Find the maximum speed vmax of the object. (d) Find the total energy E of the objectspring system. (e) Find the force constant k of the spring. (f) Describe the pattern of dependence of each of the quantities T, f, vmax, E, and k on m.arrow_forward
- A blockspring system oscillates with an amplitude of 3.50 cm. The spring constant is 250 N/m and the mass of the block is 0.500 kg. Determine (a) the mechanical energy of the system, (b) the maximum speed of the block, and (c) the maximum acceleration.arrow_forwardFor each expression, identify the angular frequency , period T, initial phase and amplitude ymax of the oscillation. All values are in SI units. a. y(t) = 0.75 cos (14.5t) b. vy (t) = 0.75 sin (14.5t + /2) c. ay (t) = 14.5 cos (0.75t + /2) 16.3arrow_forwardIf a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes 2 times as large. (c) It becomes half as large. (d) It becomes 1/2 times as large. (e) It remains the same.arrow_forward
- An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T. The object of mass m is removed and replaced with an object of mass 2m. When this object is set into oscillation, what is the period of the motion? (a) 2T (b) 2T (c) T (d) T/2 (e) T/2arrow_forwardWe do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.arrow_forwardA spherical bob of mass m and radius R is suspended from a fixed point by a rigid rod of negligible mass whose length from the point of support to the center of the bob is L (Fig. P16.75). Find the period of small oscillation. N The frequency of a physical pendulum comprising a nonuniform rod of mass 1.25 kg pivoted at one end is observed to be 0.667 Hz. The center of mass of the rod is 40.0 cm below the pivot point. What is the rotational inertia of the pendulum around its pivot point?arrow_forward
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SIMPLE HARMONIC MOTION (Physics Animation); Author: EarthPen;https://www.youtube.com/watch?v=XjkUcJkGd3Y;License: Standard YouTube License, CC-BY