A 25.00mL sample of a clear saturated solution of
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GENERAL CHEMISTRY(LL)-W/MASTERINGCHEM.
- A student is given 0.930 g of an unknown acid, which can be either oxalic acid, H2C2O4, or citric acid, H3C6H5O7. To determine which acid she has, she titrates the unknown acid with 0.615 M NaOH. The equivalence point is reached when 33.6 mL are added. What is the unknown acid?arrow_forwardOne half liter (500. mL) of 2.50 M HCl is mixed with 250. mL of 3.75 M HCl. Assuming the total solution volume after mixing is 750. mL, what is the concentration of hydrochloric acid in the resulting solution? What is its pH?arrow_forwardA solution contains Ca2+ and Pb2+ ions, both at a concentration of 0.010 M. You wish to separate the two ions from each other as completely as possible by precipitating one but not the other using aqueous Na2SO4 as the precipitating agent. (a) Which will precipitate first as sodium sulfate is added, CaSO4 or PbSO4? (b) What will be the concentration of the first ion that precipitates (Ca2+ or Pb2+) when the second, more soluble salt begins to precipitate?arrow_forward
- An artificial fruit beverage contains 12.0 g of tartaric acid, H2C4H4O6, to achieve tartness. It is titrated with a basic solution that has a density of 1.045 g/cm3 and contains 5.00 mass percent KOH. What volume of the basic solution is required? (One mole of tartaric acid reacts with two moles of hydroxide ion.)arrow_forwardThe amount of oxygen, O2, dissolved in a water sample at 25 C can be determined by titration. The first step is to add solutions of MnSO4 and NaOH to the water to convert the dissolved oxygen to MnO2. A solution of H2SO4 and KI is then added to convert the MnO2 to Mn2+, and the iodide ion is converted to I2. The I2 is then titrated with standardized Na2S2O3. (a) Balance the equation for the reaction of Mn2+ ions with O2 in basic solution. (b) Balance the equation for the reaction of MnO2 with I in acid solution. (c) Balance the equation for the reaction of S2O32 with I2. (d) Calculate the amount of O2 in 25.0 mL of water if the titration requires 2.45 mL of 0.0112 M Na2S2O3 solution.arrow_forwardChromium(III) chloride forms many compounds with ammonia. To find the formula of one of these compounds, you titrate the NH3 in the compound with standardized acid. Cr(NH3)xCl3(aq) + x HCl(aq) x NH4+(aq) + Cr3+(aq) + (x + 3) Cl(aq) Assume that 24.26 mL of 1.500 M HCl is used to titrate 1.580 g of Cr(NH3)xCl3. What is the value of x?arrow_forward
- A titration analysis of a 345.0 mL aqueous HBr solution was performed and the endpoint was reached upon the addition of 191.05 mL of 2.815 M aqueous KOH solution. What is the concentration (in M) of the HBr solution? HBr(aq) + KOH(aq) ——> KBr(aq) + H2O(l)arrow_forwardA 50.00 mL sample of a sodium hydroxide solution is titrated with a 1.605 M solution of sulfuric acid. The titration requires 24.09 mL of the acid solution to reach the end point. What is the molarity of the NaOH solution? H 2 SO 4 (aq) 2NaOH(aq) → Na 2 SO 4 (aq) 2H 2 O(l)arrow_forwardThe solubility product for Mg3(PO4)2 is 6.3 x 10‒26. What is the solubility of Mg3(PO4)2 in pure water, in grams per liter?arrow_forward
- A sample of solid calcium hydroxide, Ca(OH)2, is allowed to stand in water until a saturated solution is formed. A titration of 75.00 mL of this solution with 5.00 × 10−2 M HCl requires 36.6 mL of the acid to reach the end point.Ca(OH)2(aq) + 2HCl(aq) ⟶ CaCl2(aq) + 2H2 O(l)What is the molarity?arrow_forwardA solution of tartaric acid(H₂C₄H₄O₆)with known concentration of 0.155 M H₂C₄H₄O₆ is titrated with a 0.425 M NaOH solution.How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H₂C₄H₄O₆ ,according to the following balanced chemical equation : H₂C₄H₄O₆+ 2 NaOH→Na₂C₄H₄O₆+ 2 H₂Oarrow_forwardif 25.0g of NaOH is added to 0.750L of 1.00M Cd(NO3)2 how many grams of Cd(OH)2 will be fromed in the following precipitation reaction? 2 NaOH9aq)+ Cd(NO3)(aq)= Cd(OH)2(s)+ 2NaNO3(aq)arrow_forward
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