   # Living organisms derive energy from the oxidation of food, typified by glucose. C 6 H 12 O 6 (aq) + 6 O 2 (g) → 6 CO 2 (g) + 6 H 2 O( ℓ ) Electrons in this redox process are transferred from glucose to oxygen in a series of at least 25 steps. It is instructive to calculate the total daily current flow in a typical organism and the rate of energy expenditure (power). (See T. P. Chirpich: Journal of Chemical Education , Vol. 52, p. 99, 1975.) (a) The molar enthalpy of combustion of glucose is −2800 kJ/mol-rxn. If you are on a typical daily diet of 2400 Cal (kilocalories), what mount of glucose (in moles) must be consumed in a day if glucose is the only source of energy? What amount of O 2 must be consumed in the oxidation process? (b) How many moles of electrons must be supplied to reduce the amount of calculated in part (a)? (c) Based on the answer in part (b), calculate the current flowing, per second, in your body from the combustion of glucose. (d) If the average standard potential in the electron transport chain is 1.0 V, what is the rate of energy expenditure in watts? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 19, Problem 109SCQ
Textbook Problem
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## Living organisms derive energy from the oxidation of food, typified by glucose.C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(ℓ)Electrons in this redox process are transferred from glucose to oxygen in a series of at least 25 steps. It is instructive to calculate the total daily current flow in a typical organism and the rate of energy expenditure (power). (See T. P. Chirpich: Journal of Chemical Education, Vol. 52, p. 99, 1975.) (a) The molar enthalpy of combustion of glucose is −2800 kJ/mol-rxn. If you are on a typical daily diet of 2400 Cal (kilocalories), what mount of glucose (in moles) must be consumed in a day if glucose is the only source of energy? What amount of O2 must be consumed in the oxidation process? (b) How many moles of electrons must be supplied to reduce the amount of calculated in part (a)? (c) Based on the answer in part (b), calculate the current flowing, per second, in your body from the combustion of glucose. (d) If the average standard potential in the electron transport chain is 1.0 V, what is the rate of energy expenditure in watts?

(a)

Interpretation Introduction

Interpretation:

The amount of O2 consumed in the oxidation process has to be determined for the given reaction.

Concept introduction:

Molarity is defined as the amount of moles of a compound dissolved in an amount of solvent.

Molarity (M) = Moles soluteLitres of solute

### Explanation of Solution

To use dimensional analysis to convert this energy value into a molar amount of glucose. The negative sign is the amount of energy given off by glucose. So this value will be positive since we are converted the amount of energy consumed from glucose.

(2400 kCal)(4.184 kJ1 kCal)(1 mol-rxn2800 kJ)(1 mol glucose1 mol-rxn)   =3

(b)

Interpretation Introduction

Interpretation:

The number of moles of electrons must be supplied to reduce the amount of O2 has to be determined.

Concept introduction:

Molarity is defined as the amount of moles of a compound dissolved in an amount of solvent.

Molarity (M) = Moles soluteLitres of solute

(c)

Interpretation Introduction

Interpretation:

The current flowing per second has to be determined.

Concept introduction:

Current:

Rate of the charge which changes in time.

The formula is as follows.

Current (Amperes, A) = Electric charge (Coloumbs, C)time, t(seconds,s)

Simplify as follows.

Current = Electric charge time

(d)

Interpretation Introduction

Interpretation:

The rate of energy expenditure in watts has to be determined from the given data.

Concept introduction:

Molarity is defined as the amount of moles of a compound dissolved in an amount of solvent.

Molarity (M) = Moles soluteLitres of solute

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