Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 19, Problem 19.21SP
Rework Problem 19.20 changing the fasteners to
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Design a single riveted lap joint to connect two mild steel plates, 14.5 mm thick, the joint being designed for maximum efficiency. The allowable stresses are σt = 55 N/mm2 , = 32.5 N/mm2 and σc = 63.5 N/mm2 . Also calculate the minimum force per pitch which will rupture the joint
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Draw and label any screw thread and a fastener separately. Also, discuss the types of stresses acting on screw threads and fasteners.
Question 41. Two 10-mm-thick by 60-mm wide hot rolled SAE 1050 steel plates are to be butt-welded together with a CJP weld. Choose an appropriate electrode for tensile loading of the joint.
2. Find the torque that a 2-surface dry disk clutch can transmit if the outside and inside lining diameters are 120 mm and 70 mm, respectively, and the applied force is 10 kN. Assume uniform wear and μ = 0.4.
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- An multi axial plate clutch used in injection molding machine consist of a three pairs of contact surfaces for engaging and disengaging power from the engine. The engine used for power has a maximum torque capacity of 120 N-m and is transmitted to machine without losses. The permissible intensity of pressure is 350 kPa and the coefficient of friction is 0.35 for the clutch system used in the machine. It was determined that the machine will operate on maximum capacity of torque if the ratio of inner diameter to outside diameter of the axial clutch is 0.577. Assuming uniform wear theory, calculate the inner and outer diameters of the friction lining.arrow_forwardHow many bolts are required for LRFD and ASD for the bearing-type connection shown, if PD = 50 k and PL = 100 k? A325 3/4 in bolts, threads excluded from shear plane.arrow_forwardA flange coupling is to connect two 57 mm shafts. The hubs of the coupling are each 111 mm in diameter and 92mm thick and the flange web are 19 mm thick. Six 16 mm bolts in a 165 mm diameter circle connect the flange.The keyway is 6 mm shorter than the hub’s thickness and key is 14 mm x 14 mm. Coupling is to transmit 45 KW at160 rpm. For all parts, yield point value in shear is one – half the yield value which is 448 MPa. Calculate the forceon the shaftarrow_forward
- strength of materials 9.) Determine the width w of the plate loaded as shown if the permissible stress in plates of joints through the pin is 200MPa 10.) Design the above joint using the welded connection. The required length of the weld is:arrow_forwardDerive an expression for SF if a cantilever carrying UDL for a part of its length from the free end.arrow_forwarda) list two advantages and two disadvantages of welded joints b) Name the type of bonding forces applied in welded joints A plate 50mm wide by 11mm thick is joined with another plate 120mm wide by 11mm thick by parallel welds of 40mm long.if the permissible tensile and shear stresses are 110MPa and 80MPa respectively calculate; i) safe load F carried by the joint ii) Efficiency of the jointarrow_forward
- The allowable stresses for the splice shown are the following: 150 MPa for shear of rivets, 1.35Fy for bearing,0.60Fy for tension and Fy = 250 MPa. Note: rivet holes are 2 mm bigger than the rivet diameter and the middleplate is 20 mm thick. Find the diameter of the rivets so that the joint capacity due to shear approximately equal to the bearingcapacity.a. 25.4 mm c. 28.65 mmb. 30.79 mm d. 36.97 mm Find the maximum safe value of P without exceeding the allowable shearing stressa. 773.6 kN c. 938.3 kNb. 878.1 kN d. 848.2 kN Find the maximum safe value of P without exceeding the allowable tensile stress.a. 579.3 kN c. 716.1 kNb. 495.5 kN d. 692.5 kNarrow_forwardTe - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /Ymwarrow_forwardThe double-offset joint is typically used in applica tions that require______. a. higher operating angles and greater plunge depth b. lower operating angles and lower plunge depth c. higher operating angles and lower plunge depth d. lower operating angles and greater plunge deptharrow_forward
- A steel tubing has a 1.5-in outside diameter and a 1.210-in inside diameter. It is made of AISI 1020 annealed steel having a tensile strength of 57,000 psi. What would be the safe working pressure for this tube assuming a factor of safety of 8?arrow_forwardCalculate the total required shear area for this connection.arrow_forwardA double riveted lap joint with chain riveting is to be made for joining two plates 10 mm thick. The allowable stresses are : o, = 60 MPa; T= 50 MPa and o. = 80 MPa. Find the rivet diameter, pitch of rivets and distance between rows of rivets. Also find the efficiency of the joint.arrow_forward
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