Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 19, Problem 19.3P
Rework Problem
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
How many bolts are required for LRFD and ASD for the bearing-type connection shown, if PD = 50 k and PL = 100 k?
A325 3/4 in bolts, threads excluded from shear plane.
A flange coupling connects two 2” diameter shafts. The flanges are fitted with 6 bolts of SAE 1040 steel on a 7” bolt circle. The shafts runs at 300 rpm and transmits 45 hp. Assume a factor of safety of 5, ultimate tension of 70,000 psi, and ultimate shear of 55,000 psi. Determine:
a) The torque transmitted, in-lbs b) The force applied per bolt, lbs c) The diameter of the bolt required, in d) The thickness of flanged to be used, in
3. Find the power that can be safely transmitted by a flange type shaft coupling, if it has four equally spaced studs all at a radius of 50 mm from the shaft centre. The mean stud diameters are 12.5 mm, and each stud has a maximum safe working shear stress of 86 MPa. The shaft rotates at 3600 rpm.
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- If the maximum permissible shearing stress is 10,000 psi, how many 3/8'' bolts arranged in a 5'' diameter bolt circle are required to transmit 100 hp at 315 rpm through a flanged coupling.arrow_forwardI want proper solution don't copy from others solution I will report. flange coupling connects two 50 mm diameter lengths of commercial shafting. The coupling flanges are bolted together with four bolts of the same material as the shaft. The bolts are set in clearance holes. The diameter of the bolt circle is 240 mm and the flange thickness is 22 mm, (1) Determine the minimum bolt diameter required to transmit the same torque that the shaft can transmit.arrow_forwardThe rivets are 25-mm in diameter, A502, Grade 1, hot driven, with allowable shearing stress of 120 MPa. Assume the plates are adequate to transfer load to the rivets. P = 40 kN. 1. Which of the following most nearly gives the shearing stress on the most stressed rivet in MPa? a. 61 b. 68 c. 74 d. 83 2. of the following most nearly gives the maximum eccentricity in mm, if the load P is maintained? a. 756 b. 670 c. 445 d. 522 3. Which of the following most nearly gives the maximum load P in kN if the eccentricity is maintained? a. 72 b. 85 c. 68 d. 58arrow_forward
- A winch drum of diameter 161 mm turning at 12pm lifts a load of 7.5kN. What is the winch output power?arrow_forwardA belt is to transmit 50 kW power to a machine. The sheave is 10 inches in diameter and turns at 1200 rpm, while the larger sheave turns at 500 rpm. Determine the design HP if a service factor of 1.35 and a correction factor of 0.85.arrow_forwardIn the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa 1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar? a. 0.454 b. 0.9 c. 0.838 d. 0.869 2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2 a. 463.83 kN…arrow_forward
- 1. A jack having square threads of 50 mm nominal diameter and 10 mm pitch is supporting a load of 89 kN. A double thread is used and the coefficient of friction maybe as low as 0.10 or as high as 0.15.c. What maximum torque is necessary to lower the load?d. What is the maximum torsional shear stress induced on the screw?arrow_forward1. A jack having square threads of 50 mm nominal diameter and 10 mm pitch is supporting a load of 89 kN. A double thread is used and the coefficient of friction maybe as low as 0.10 or as high as 0.15.a. Will this screw always self-locking?b. What is the highest torque necessary to raise the load?arrow_forwardQuestion No.15: Design muff coupling to connect two steel shafts transmitting 40 kW at 350 rpm. The material for shafts and key is plain carbon steel for which allowable shear and crushing stresses are 40 MPa and 80 MPa respectively. The material for muff is cast iron for which allowable shear stress is 15 Mpaarrow_forward
- Two short shafts with identical diameters of 38.1 mm are connected by a coupling which is fitted with 4 - bolts on a 100 mm bolt circle. The shaft runs at a speed of 400 rpm. The design shearing stress of the bolts is 12 N/mm and the design compressive stress of flanges is 15 N/mm. What is the power transmitted by the short shaft in kW? A. 24.1 kW B. 22.7 kW C. 26.5 kW D. 28.3 kW What diameter of the bolt should be used? A. 18.32 mm B. 20.64 mm C. 16.28 mm D. 14.46 mm How thick should the flanges be in mm? A. 13.02 mm B. 15.54 mm C. 9.07 mm D. 11.51 mmarrow_forwardA diagrammatic representation of a universal joint is shown, two yoke parts, the type being similar to Figs. 10.28 and 12.10, Text. The pin extensions have a diameter D = ¾ in.; a = 11/16 in., material of all parts is 4340, OQT Let N = 4 on ultimate stresses; n = 2400 rpm. Compute the safe torque for (a) shear of pins, (b) the pin extensions in bending, assuming that the load distribution is from zero at the outside pin ends to a maximum at the inside yoke surfaces, (c) an average bearing pressure on pins of 4 ksi. (d) What is the corresponding horsepower capacity?arrow_forward3) A flange coupling is to connect two 60mm shafts. The hubs of the coupling are 120mm, 100mm thick, & the flange webs are 20 mm thick. Six M16 bolts fasten the flange from a 165 bolt circle. The keyway is 15mm shorter than the hub’s thickness & the key is 15mm x 15mm. The coupling transmits 45kW @ 450rpm. The yield point in shear for all materials is half of its yield point in tension or compression. Yield tensile strength is 0.75 of ultimate strength of the materials. The Sult is 448N/mm2 . Find: (a) the shear stress in key; (b) the bearing stress in key; (c) the shear stress in bolts; (d) bearing stress in flange.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License