Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840728
Author: Limbrunner
Publisher: PEARSON
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Chapter 19, Problem 19.26SP
The welded connection shown is subjected to an axial tensile load P of 100,000 lb. Calculate the minimum size fillet weld required the length L is 7 in. Assume an E70 electrode.
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A bracket, as shown in figure below, is welded to a plate. The welds have the same size, and thepermissible force per mm of the weld-length is 1 kN. Calculate the lengths l1 and l2.
(1) What are the methods used to obtain a good weld when welding steel when the carbon content is high? b) Find the appropriate size and length for the weld joint shown in the figure if the strength is equal to (70000Ib) and the allowable shear stress value is 40ksi and the weld rib dimension is (1/4in)
a) list two advantages and two disadvantages of welded joints
b) Name the type of bonding forces applied in welded joints
A plate 50mm wide by 11mm thick is joined with another plate 120mm wide by 11mm thick by parallel welds of 40mm long.if the permissible tensile and shear stresses are 110MPa and 80MPa respectively calculate;
i) safe load F carried by the joint
ii) Efficiency of the joint
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- Question: a) A plate 100 mm wide and 10 mm thick is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 80 kN. Find the length of weld if the permissible shear stress in the weld does not exceed 55MPa. Determine the increase in load carrying capacity if a combination of single transverse double parallel fillet is used the permissible tensile strength of material is 80MPa. b) Draw a neat sketch of double riveted double cover but joint. If 8mm plates with 20 mm diameter rivets having a pitch of 50 mm are joint using double riveted lap joint. The permissible stresses are permissible tensile stress = 120 MPa;Permissible crushing stress= 100 MPa; Permissble shear stess= 150 MPa. Find the strengths and efficiency of joint, taking the strength of the rivet in double shear acoording to the indian boiler standards.arrow_forwardA plate 100 mm wide and 10 mm thick is to be welded with another plate by means of transverse welds at the ends. If the plates are subjected to a load of 70 kN, find the size of weld for static load The permissible tensile stress should not exceed 70 MPa.arrow_forwardA bracket is as shown in figure 2. Determine the uniform weld size for the arrangement. The permissible shear stress of weld material is 80 MPa. Consider the loading condition as shown in figure.arrow_forward
- A bracket, as shown in Fig below, carries a load of 40 kN. Calculate the size of weld, if the allowable shear stress is not to exceed 80 MPa. All dimensions in mm.arrow_forwardI need right solution with clear calculations. Two steel plates having yield point stress of 350 N/mm2 are joined together by double fillet welds of 10 mm thick as shown in figure. The weldment is from the same parent plate material. If the weld has to be replaced by 3 bolts of the same material, one each at A and B and one at mid-way between C and D, design the bolts. Take factor of safety as 2 for the boltsarrow_forwardappropriate length of the weld joint shown in the figure if the force is equal to (60000lb) and the operating stress value is (60ksi) and the size of the weld is (1/4in).arrow_forward
- A cylindrical air-compressor tank with an inside diameter of 50 mm is to be designed to withstand safely a working pressure of 0.86 MPa. Boiler plate with an allowable tensile stress of 76 MPa. All seams will be butt welds with an expected efficiency of 100 percent. a.) Determine the force per lineal mm of longitudinal seam, b.) Determine the required thickness “t” of wall, c.) Determine the unit stress in the circumferential seam.arrow_forwardTe - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /Ymwarrow_forwardA welded joint, as shown in figure below, is subjected to an eccentric load of 2500 N. Find thesize of the weld, if the maximum shear stress in the weld is not to exceed 50 N/mm2arrow_forward
- A rectangular steel plate is welded as a cantilever to a vertical column and supports a single concentrated load P. Determine the weld size if shear stress in the same is not to exceed 140 MPaarrow_forwardDesign a single riveted lap joint to connect two mild steel plates, 14.5 mm thick, the joint being designed for maximum efficiency. The allowable stresses are σt = 55 N/mm2 , = 32.5 N/mm2 and σc = 63.5 N/mm2 . Also calculate the minimum force per pitch which will rupture the jointarrow_forwardQuestion No. 11: (a) Illustrate flatness, straightness and circularity with symbol. (b) A circular shaft, 80 mm in diameter is welded to support by means of a circumferential fillet weld. It is subjected to a torsion moment of 3000 N-m. Determine the size of weld, if the maximum shear stress in the weld is not to exceed 70 N/mm2 . (c) Analyze different stresses during design of screw and nutarrow_forward
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