EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 19, Problem 19.32P
Interpretation Introduction
Interpretation:
The structure of imine derivative of pyridoxal phosphate with the lysine residue of protein is to be drawn.
Concept introduction:
The chemical compounds that consist of a double bond between carbon and nitrogen atom
The chemical compounds in which carbon is bonded with the acidic and basic group along with hydrocarbon side chain are known as amino acids. They combine sequentially to generate a protein.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Calculate the percentage of free acid for (a) phenobarbital (it is an acid with pKa = 7.40) and (b) hexobarbital (also an acid with pKa = 8.4) at the physiological condition of pH 7.4.
Pyridine forms a stronger Lewis acid-base complex with SO3 than SO2. However, pyridine forms a weaker complex with SF6 than with SF4. Explain the difference.
22.47 Tertiary amines with three different alkyl groups are chiral but cannot be resolved because pyramidal
inversion causes racemization at room temperature. Nevertheless, chiral aziridines can be resolved and stored
at room temperature. Aziridine is a three-membered heterocycle containing a nitrogen atom. The following is
an example of a chiral aziridine. In this compound, the nitrogen atom is a chiral center. Suggest a reason why
chiral aziridines do not undergo racemization at room temperature.
Chapter 19 Solutions
EBK ORGANIC CHEMISTRY
Ch. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Prob. 19.3PCh. 19 - Prob. 19.4PCh. 19 - Prob. 19.5PCh. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - Prob. 19.8PCh. 19 - Prob. 19.9PCh. 19 - Prob. 19.10P
Ch. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25PCh. 19 - Prob. 19.26PCh. 19 - Prob. 19.27PCh. 19 - Prob. 19.28PCh. 19 - Prob. 19.29PCh. 19 - Prob. 19.30PCh. 19 - Prob. 19.31PCh. 19 - Prob. 19.32PCh. 19 - Prob. 19.33PCh. 19 - Prob. 19.34PCh. 19 - Prob. 19.35PCh. 19 - Prob. 19.36PCh. 19 - Prob. 19.37PCh. 19 - Prob. 19.38PCh. 19 - Prob. 19.39PCh. 19 - Prob. 19.40APCh. 19 - Prob. 19.41APCh. 19 - Prob. 19.42APCh. 19 - Prob. 19.43APCh. 19 - Prob. 19.44APCh. 19 - Prob. 19.45APCh. 19 - Prob. 19.46APCh. 19 - Prob. 19.47APCh. 19 - Prob. 19.48APCh. 19 - Prob. 19.49APCh. 19 - Prob. 19.50APCh. 19 - Prob. 19.51APCh. 19 - Prob. 19.53APCh. 19 - Prob. 19.54APCh. 19 - Prob. 19.55APCh. 19 - Prob. 19.56APCh. 19 - Prob. 19.57APCh. 19 - Prob. 19.58APCh. 19 - Prob. 19.59APCh. 19 - Prob. 19.60APCh. 19 - Prob. 19.61APCh. 19 - Prob. 19.62APCh. 19 - Prob. 19.63APCh. 19 - Prob. 19.64APCh. 19 - Prob. 19.65APCh. 19 - Prob. 19.66APCh. 19 - Prob. 19.67APCh. 19 - Prob. 19.68APCh. 19 - Prob. 19.69APCh. 19 - Prob. 19.70APCh. 19 - Prob. 19.71APCh. 19 - Prob. 19.72AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- (i) Why do actinoids show wide range of oxidation states? (ii) Why is actinoid contraction greater than lanthanoid contraction?arrow_forward9. Phosphotyrosine (shown below) has four ionizable functional groups (pK1 = 2.5, pKR1 = 2.1, pKr2 = 7.2, pK2 = 9.5). (a) Write the equilibrium equation for its four ionization forms and assign the proper pka for each ionization. DRAW the structure of phosphotyrosine in each ionization state. What is the net charge on the phosphotyrosine molecule in each ionization state? *H3N. pk2 - 9.5 .COOH pK, - 2.5 O=P-OH pKRI - 2.1 ÖH pKRI - 7.2 (b) Draw the titration curve of phosphorotyrosine and indicate each pKa and the isoelectric point (pl), indicate the molar equivalents of OH on the x-axis.arrow_forwardSuppose you have a mixture of these three compounds. Devise a chemical procedure based on their relative acidity or basicity to separate and isolate each in pure form.arrow_forward
- Several compounds have been found to inhibit -lactamase, and drugs based on these compounds can be taken in combination with penicillins and cephalosporins to restore their effectiveness when resistance is known to be a problem. The commonly prescribed formulation called Augmentin is a combination of the -lactamase inhibitor shown below with amoxicillin (shown above). It is used to treat childhood ear infections when resistance is suspected, and many kids know it as the white liquid that tastes like bananas. Which of the statements below are true statements? 1. The stereochemistry of the fusion between the four-and five-membered rings in the inhibitor and amoxicillin are different. 2. The inhibitor possesses enol ether and allylic alcohol functional groups while the antibiotic possesses a phenol and a secondary amide functional group. 3. Neither the inhibitor nor the antibiotic contains strained rings. 4. Both 1 and 2 are true.arrow_forwardWrite the chemical formula and give the name of the anhydride corresponding to each of the following acids orbases, and identify it as an acid or base anhydride.(a) H3AsO4 (b) H2MoO4(c) RbOH (d) H2SO3arrow_forwardAniline (conjugate acid pKa 4.63) is a considerably stronger base than diphenylamine (pKa 0.79). Account for these marked differences.arrow_forward
- Chlorophyll, heme, vitamin B12, and a host of other substances are synthesized from porphobilinogen, which is itself formed from the condensation of two molecules of 5-aminolevulinate. The two 5-aminolevulinates are bound to lysine (Lys) residues in the enzyme, one in the enamine form and the other in the imine form. Condensation is thought to occur via a several step process, one of which is shown below. ÇO2 ÇO2 CO2 + NH3 NH3 H H3N 5-aminolevulinate (enamine form) 5-aminolevulinate (imine form) Porphobilinogen Draw curved arrows to illustrate the movement of electrons in this step of the reaction. Arrow-pushing Instructions CO2 CO2 CO2 CO2 :B BH* H-A H3N H3Ņarrow_forwardGiven the Ka values (in parentheses) for the following acids: HSO4– (Ka= 1.2 x 10–2); HNO2 (Ka= 4.0 x 10–4); HC2H3O2 (Ka= 1.8 x 10–5); Calculate Kc values for the following acid-base equilibria: (a) HSO4–(aq) + C2H3O2–(aq) ⇌ HC2H3O2(aq) + SO42–(aq) (b) HC2H3O2(aq) + NO2–(aq) ⇌ HNO2(aq)+ C2H3O2–(aq)arrow_forwardAt pH 3.0, what percentage (in %) of lactic acid is in its deprotonated form? Hint: The pka of lactic acid is 3.86.arrow_forward
- There are a number of pharmacokinetic strategies available to change the absorption of a lead compound during the drug design process. (a) Based on the lead compound shown, draw an analogue which has decreased polarity using two different strategies. The drawing can be done neatly by hand or by using ChemDraw. (b) Clearly label your analogue with the strategy being used for each change. (c) State whether your analogue will be more hydrophillic or hydrophobic than the original lead compound shown. (d) Attach a clear photo of your handwritten structure and answers using an image file or upload a PDF, Powerpoint or Word file containing your ChemDraw structure and answers. SO,Me N. CH3arrow_forwardQuinuclidine and triethylamine are both tertiary amines. Quinuclidine, however, is a considerably stronger base than triethylamine. Stated alternatively, the con- jugate acid of quinuclidine is a considerably weaker acid than the conjugate acid of triethylamine. Quinuclidine pK, 10.6 Triethylamine pK, 8.6 Propose an explanation for these differences in acidity/basicity.arrow_forwardH3A is a triprotic acid. What would be the molecular formula of the conjugate acid of HA2-(aq)?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning