(a) Interpretation: The value of K for the given reaction at 25 ° C should be calculated. Ni(s) + 2 V 3+ (aq) → 2 V 2+ ( aq ) + Ni 2+ (aq) Concept introduction: The E° c e l l value for a redox reaction gives by following equation. E ° c e l l = E ° R e d u c t i o n − E ° O x i d a t i o n When the reactants and products are in their standard states, Δ r G ∘ = − z F E c e l l ∘ Where, z = Electron number F = Faraday constant = 96 , 485 C mol − 1 E c e l l ∘ = Standard Electron cell potential The electron number, z, for a reaction depends on how the reaction is written. Δ r G ∘ = − RT ln K − RT ln K = − z F E c e l l ∘ ∴ ln K = − z F E c e l l ∘ − R T ln K = 11604 C J -1 z E c e l l ∘ T K = e 11604 C J -1 z E c e l l ∘ T

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Answer 1

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Answer 2

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Answer 3

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Answer 4

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Answer 5

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 6

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 7

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 8

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 9

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 10

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 11

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Solution Summary: The author explains how the value of K for the given reaction at 25 ° C should be calculated.

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