Manufacturing Processes for Engineering Materials (6th Edition)
6th Edition
ISBN: 9780134290553
Author: Serope Kalpakjian, Steven Schmid
Publisher: PEARSON
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Chapter 2, Problem 2.21Q
To determine
Explain the reason for the elliptical impression is obtained in Brinell hardness test.
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Determine Brinell Hardness Number for a specimen that has a surface area of indentation as 19 mm2 and the applied force as 12 kN.
(SI/USCS Units) In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting indentation has a diameter = 3.2 mm. (a) Determine the Brinell hardness number for the metal. (b) If the specimen is steel, estimate the tensile strength of the steel.
Determine the surface area of indentation for a specimen that has Brinell hardness number as 851 and the applied force as 15 kN.
Chapter 2 Solutions
Manufacturing Processes for Engineering Materials (6th Edition)
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- A mild steel material is subjected to a Brinell hardness test with an applied force of 9469 N using a hardened steel ball indentor of 9 mm and it is found that the Brinell Hardness Number as 912. Determine the surface area of indentation and indentation diameter.arrow_forwardDetermine Brinell Hardness Number for a specimen that has a surface area of indentation as 12 mm2 and the applied force as 15 kN. Brinell Hardness Number =arrow_forwardin tensile test data, show step by step how to find stress and strain in aluminiumarrow_forward
- If the true stress is 74 MPa for the specimen described above elongated by 2.6 cm, what is the difference between nominal and true stress in MPa (absolute value)?arrow_forwardA hardened aluminium ball of 0.5 cm diameter is used to indent a aluminium specimen in Brinell hardness test. Diameter of indentation measured by an optical microscope of magnification 10 x is observed to be 32.5 mm Calculate Brinell Hardness Number of the aluminium specimenarrow_forwardBy performing torsion tests, which develop pure shear in a ductile specimen, does the maximum distortion energy theory accurate results?arrow_forward
- 1) What is the shear modulus and how can it be obtained from a torsion test? 2) Explain why it is necessary to consider geometric factors when determining distortion in torsional testing.arrow_forwardBriefly discuss the differences between the Engineering Stress versus Engineering Strain and the True Stress versus True Strain Diagrams for the test specimen. Briefly explain why the two plots are different. When is the use of Engineering Stress versus Engineering Strain invalid?arrow_forwardBriefly comment on the values obtained for the Elastic Modulus, Yield Strength, Ultimate Strength and Toughness of the test specimen as compared to values of various comparable materials found in the literature. Is the test material comparatively strong? Is it stiff? Is it tough? Yield strength is 186Mpa, elastic modulus is 44.8GPa And the ultimate strength is 238.7mpaarrow_forward
- For a 10-mm-diameter Brinell hardness indenter, what will be the diameter of an indentation in mm to yield a hardness of 506 HB when a 500-kg load is used?arrow_forwardA tensile specimen is elongated to twice its original length. Determine the engineering strain and true strain for this test? If the values are different explanations why they are different?arrow_forward(SI Units) In a tensile test on a steel specimen, true strain = 0.11 at a stress of 245 MPa. When true stress = 340 MPa, true strain = 0.31. Determine the strength coefficient and the strain-hardening exponent in the flow curve equation.arrow_forward
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