Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
6th Edition
ISBN: 9780137503520
Author: Serope Kalpakjian, Steven Schmid
Publisher: PEARSON+
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Question
Chapter 2, Problem 2.93P
(a)
To determine
The stress strain relationship for this material.
(b)
To determine
The ultimate tensile strength for this material.
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Chapter 2 Solutions
Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- A cylindrical bar of metal having a diameter of 18.3 mm and a length of 209 mm is deformed elastically in tension with a force of 52500 N. Given that the elastic modulus and Poisson's ratio of the metal are 68.2 GPa and 0.33, respectively, determine the following: (a) The amount by which this specimen will elongate in the direction of the applied stress. (in mm) (b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number. (in mm)arrow_forwardA tensile force of 200 KN is applied on a 0.02-m diameter and.2-m long rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length increases to 2.01 m. Assuming no permanent deformation occurs in that material, the modulus of elasticity (GPa) is?arrow_forwardWhat is the stress-strain curves of materials?arrow_forward
- A tensile force of 10 kN is applied on a 0.02-m diameter and 2-m long rod. After applying theload, the diameter of the rod decreases to 0.01998 m and the length increases to 2.01 m. The lateral (transverse) strain is?arrow_forwardStress (MPa) 500 400 Consider the brass alloy for which the stress-strain behavior is shown in the Animated Figure 7.12. A cylindrical specimen of this material 9.9mm (0.3898 in.) in diameter and 98.8mm (3.890 in.) long is pulled in tension with a force of 9780N(2199/b). If it is known that this alloy has a value for Poisson's ratio of 0.35, compute (a) the specimen elongation, (b) the reduction in specimen diameter. Note: because the diameter decreases, enter a minus sign in your answer. Tensile strength 450 MPa (65,000 psi), Strain =0 Stress = 0 MPA Stress =0 psi 70 Strain = 0 Stress 0 MPA 60 Stress = 0 psi 103 psi 50 40 MPa Yield strength 300 250 MPa (36,000 psi) 40 30 200 200 20 100 10 100 0 0 T 10 P 0.10 0.20 Strain 10.065 0 0.30 0.40 30 20 10 Stress (10 psi)arrow_forwardWhich of the following is an accurate statement? (A) The lateral strain is greater than the axial strain. (B) The axial strain is greater than the lateral strain. (C) The lateral is twice that of axial strain. (D) The axial strain is twice that of the lateral strain.arrow_forward
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