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Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
6th Edition
ISBN: 9780137503520
Author: Serope Kalpakjian, Steven Schmid
Publisher: PEARSON+
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Question
Chapter 2, Problem 2.13Q
To determine
The reason that deformation rate and true strain rate are not same.
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Students have asked these similar questions
2) The strength coefficient and strain-hardening exponent of a certain test metal are 750
MPa and 0.25, respectively. A cylindrical specimen of the metal with starting diameter
= 75 mm is stretched. If the average flow stress on the part is 450 MPa determine the
final diameter of the specimen.
With a suitable example explain the difference between True stress-strain and Engineering stress- strain.
In True stress-true-strain curve in tension of solid metal cylinder 45 mm high and 8 mm in diameter, two
pairs of values of stress and strain were given for the specimen metal after it had yielded (1) true stress =
217 MPa, and true strain = 0.35; and (2) true stress = 259 MPa, and true strain = 0.68. Based on these data
points, determine the following:
a) The average flow stress that the metal experiences if it is subjected to a stress that is equal to its
strength coefficient K.
b) The work done that the metal experiences if it is subjected to elongation in height of 45%
c) If during the deformation the relative speed = 20 mm/s, determine the strain rate at h = 50 mm and
h = 70 mm.
Chapter 2 Solutions
Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- "The maximum principal stress yield criterion is an appropriate choice for ductile materials but the maximum principal strain criterion is preferable". Is this true or false?arrow_forwardWhen the true strain equals 0.14 and the true stress equals 355 MPa, the tensile test specimen starts to neck. Find the strength coefficient and the strain-hardening exponent in the flow curve equation without knowing any more about the test.arrow_forwardExplain EXTERNAL WORK AND STRAIN ENERGY?arrow_forward
- 2. The flow curve parameters for a certain stainless steel are strength coefficient = 1100 MPa and strain-hardening exponent = 0.35. A cylindrical specimen of starting cross-sectional area = 1000 mm? and height = 75 mm is compressed to a height of 58 mm. Determine the force required to achieve this compression, assuming that the cross section increases uniformly.arrow_forwardA cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is pulled in tension with a force of 40, 000 N. If the deformation is totally elastic, what is the strain experienced by the specimen along the lateral direction?arrow_forwardWrite out the most general expression for shear strain along a single axis resulting from all possible applied stresses, assuming that the material is elastically isotropic.arrow_forward
- In open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling effect. The final diameter of the disc is 400 mm. The true strain isarrow_forwardA cylindrical specimen of brass that has a diameter of 15 mm, a tensile modulus of 120 GPa, and a Poisson’s ratio of 0.30 is pulled in tension with force of 50,000 N. If the deformation is totally elastic, what is the approximate strain experienced by the specimen?arrow_forwardStress can be related to strain. Explain by using experimental methods?arrow_forward
- 1. What are the elastic modulus (E) and the Poisson's ratio () used to indicate? 2. Illustrate the differences between actual stress and engineered stress with strain, and also describe their underlying physical concepts. 3. If the engineering strain is 2% for a specific state of uniaxial stress, what is the real strain? Please solve for all in full detail and step by steparrow_forwardBy performing torsion tests, which develop pure shear in a ductile specimen, does the maximum distortion energy theory accurate results?arrow_forwardA material has a strength coefficient of 150,000 psi. At the onset of plastic deformation, the material had an 18 percent increase over its initial length, and at the beginning of non-uniform deformation, the material experienced an engineering strain of 0.58. Calculate the engineering and true strains at yield. Also, calculate the engineering and true strains at the point where a maximum engineering stress is experienced by the material. Determine the strain-hardening index. Calculate the ultimate tensile strength. Calculate the modulus of elasticity. Given: K = 150,000 psi 18% increase in length ey = 0.58 Want: ey =? eu =? n =? UTS =? E =? εy =? εu =?arrow_forward
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