Concept explainers
(a)
Engineering stress and engineering strain.
(a)
Answer to Problem 2.95P
The value of engineering stress is
Hence the value of engineering strain is 0.96.
Explanation of Solution
Given data:
The engineering stress and engineering strain.
A tensile load is applied to a solid bar. The bar deforms uniformly and the volume remains constant.
Calculating the initial area of the solid bar,
Calculating the final area of the solid bar,
Writing the formula for engineering stress,
Writing the formula for engineering strain,
Hence the value of engineering strain is 0.96.
(b)
True stress and true strain
(b)
Answer to Problem 2.95P
The value of true strain is 0.673.
Explanation of Solution
Writing the formula for true stress,
Writing the formula for true strain,
Hence, the value of true strain is 0.673.
(c)
The engineering stress and engineering strain when the true stress is
(c)
Answer to Problem 2.95P
The value of engineering stress is
The value of engineering strain is 0.5625.
Explanation of Solution
Now if the given condition is −
The final area can be given as,
From the true stress formula,
Hence the value of engineering stress is
From equation (1),
Hence the value of engineering strain is 0.5625.
Want to see more full solutions like this?
Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
- A cylindrical specimen of brass that has a diameter of 21 mm, a tensile modulus of 122 GPa, and a Poisson’s ratio of 0.37 is pulled in tension with force of 38704 N. If the deformation is totally elastic, what is the strain experienced by the specimen?arrow_forwardWhat type of behaviour is observed from these stress-strain curves?arrow_forwardBriefly comment on the values obtained for the Elastic Modulus, Yield Strength, Ultimate Strength and Toughness of the test specimen as compared to values of various comparable materials found in the literature. Is the test material comparatively strong? Is it stiff? Is it tough? Yield strength is 186Mpa, elastic modulus is 44.8GPa And the ultimate strength is 238.7mpaarrow_forward
- A material has a strength coefficient of 150,000 psi. At the onset of plastic deformation, the material had an 18 percent increase over its initial length, and at the beginning of non-uniform deformation, the material experienced an engineering strain of 0.58. Calculate the engineering and true strains at yield. Also, calculate the engineering and true strains at the point where a maximum engineering stress is experienced by the material. Determine the strain-hardening index. Calculate the ultimate tensile strength. Calculate the modulus of elasticity. Given: K = 150,000 psi 18% increase in length ey = 0.58 Want: ey =? eu =? n =? UTS =? E =? εy =? εu =?arrow_forward(SI Units) In a tensile test on a steel specimen, true strain = 0.11 at a stress of 245 MPa. When true stress = 340 MPa, true strain = 0.31. Determine the strength coefficient and the strain-hardening exponent in the flow curve equation.arrow_forwardA cylindrical specimen of brass that has a diameter of 15 mm, a tensile modulus of 120 GPa, and a Poisson’s ratio of 0.30 is pulled in tension with force of 50,000 N. If the deformation is totally elastic, what is the approximate strain experienced by the specimen?arrow_forward
- How can the principal normal strains and maximum in-plane shear strain be determined?arrow_forwardA cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is pulled in tension with a force of 40, 000 N. If the deformation is totally elastic, what is the strain experienced by the specimen along the lateral direction?arrow_forwardA cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is pulled in tension with a force of 40, 000 N. If the deformation is totally elastic, what is the strain experienced by the specimen along the longitudinal direction?arrow_forward
- Write out the most general expression for shear strain along a single axis resulting from all possible applied stresses, assuming that the material is elastically isotropic.arrow_forwardDraw a typical stress vs strain tensile test curve for the following material and label the axis. A typical brittle material subjected to a tensile stress that has been applied to the material till the sample breaks. 1- label the axis and draw the curve for a brittle material. 2- indicate the maximum strength of the material. 3- show on the portion of the curve where young's modulus can be calculated.arrow_forwardHow are Engineering stress and strain calculated?arrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY