EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Question
Chapter 2, Problem 2.9Q
To determine
Whether the specific work divide by volume of the specimen under the stress-strain curve and load elongation curve represents same or not also explain whether it is same for all the value of strain or not.
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Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- Can we determine the relationship between the average normal stress and average normal strain by performing the tension test?arrow_forwardThe following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 157 kN. - Length of the specimen is 23 mm. - The yield strength is 89 kN/mm2. - The percentage of elongation is 45 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1.3 mm at 18 kN and Final diameter if the percentage of reduction in area is 25 %. Fine this ans 1-Initial Cross-sectional Area (in mm2) 2-The Diameter of the Specimen (in mm) 3-Final Length of the Specimen (in mm) 4-Stress at the elastic load (in N/mm2) 5-Young's Modulus of the Specimen (in N/mm2) 6-Final Area of the Specimen at Fracture (in mm) 7-Final Diameter of the Specimen after Fracture (in mm)arrow_forwardThe following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 143 kN. - Length of the specimen is 29 mm. - The yield strength is 71 kN/mm2. - The percentage of elongation is 48 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1 mm at 18 kN and Final diameter if the percentage of reduction in area is 29 %. Initial Cross-sectional Area 2.01 mm2. The Diameter of the Specimen 1.59 mm. Final Length of the Specimen 42.92 mm. Stress at the elastic load 8955.22 N/mm2. Find: Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)arrow_forward
- The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 143 kN. - Length of the specimen is 29 mm. - The yield strength is 71 kN/mm2. - The percentage of elongation is 48 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1 mm at 18 kN and Final diameter if the percentage of reduction in area is 29 %. FIND: Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)arrow_forward"The maximum principal stress yield criterion is an appropriate choice for ductile materials but the maximum principal strain criterion is preferable". Is this true or false?arrow_forwardTensile test is a method to investigate the elasticity of a material. A test specimen is placed between two clamps and these clamps will move in opposite directions, hence straining the test specimen. This experiment will yield a stress-strain curve that shows each of the stages of the specimen for every load is applied. With an aid of sketching diagrams, describe the stages that the specimen experiences before it breaks, and relate it with the stress-strain curve. It is expected that each stage comes with a sketching of the specimen and explanation of the current stage.arrow_forward
- Briefly comment on the values obtained for the Elastic Modulus, Yield Strength, Ultimate Strength and Toughness of the test specimen as compared to values of various comparable materials found in the literature. Is the test material comparatively strong? Is it stiff? Is it tough? Yield strength is 186Mpa, elastic modulus is 44.8GPa And the ultimate strength is 238.7mpaarrow_forwardIn the First project: you have been asked to perform tensile testing for four different materialsand analyse the results and work on some NDT process selection:a. For the results shown in Table 1 of the tensile testing that you have performed, find thefollowing, if you know that the original length of specimen is 20.8 mm and the original diameteris 6.4 mm. Fill the calculated results in the summary table below (Table 1):1. Plot the engineering stress versus engineering strain for each material and L-D Diagram.2. Compute the modulus of elasticity, E in GPa.3. Determine the yield strength at a strain offset of 0.002.4. Determine the tensile strength in MPa.5. What is the approximate %El ductility, measured by percent elongation?6. Compute the modulus of resilience.7. Determine the fracture stress in MPa.8. Compute the final area (Af) in mm2.arrow_forwardWas there a discrepancy between the values of Young's Modulus found in the tensile test and the bending test? If so, why does this occur?arrow_forward
- How is the nominal or engineering strain found directly from the strain gage?arrow_forwardThe following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 147 kN. - Length of the specimen is 28 mm. - The yield strength is 75 kN/mm2. - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 16 kN, iv) Young's Modulus if the elongation is 1 mm at 16 kN and (v) Final diameter if the percentage of reduction in area is 22 Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm) Initial Cross-sectional Area (in mm2)arrow_forwardThe magnitude of the shear stress to cause yielding in a torsion test and the magnitude of the normal stress to cause yielding in a uniaxial tensile test are usually equal". Is this true or false?arrow_forward
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