   # You combine 1.25 g of germanium, Ge, with excess chlorine, Cl 2 . The mass of product, Ge x Cl y , is 3.69 g. What is the formula of the product, Ce x Cl y ? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 2, Problem 96PS
Textbook Problem
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## You combine 1.25 g of germanium, Ge, with excess chlorine, Cl2. The mass of product, GexCly, is 3.69 g. What is the formula of the product, CexCly?

Interpretation Introduction

Interpretation: The formula of the given product GexCly is to be determined if 1.25g  of Ge is react with ozone to form the product.

Concept introduction:

• Empirical formula of a compound represents the smallest whole number relative ratio of elements in that compound.
• Equation for number moles from mass and molar mass,

Numberofmoles=MassingramsMolarmass

### Explanation of Solution

The mass of the product GexCly is given that 3.69g.

The mass of the gallium (Ge) in product is given that 1.25g

So, the mass of Cl in product GexCly is,

3.69gGexCly1.25gGe=2.44gCl

Equation for number of moles from mass and molar mass is,

Numberofmoles=MassingramsMolarmass

Therefore,

The number of moles of Ge is,

Numberofmoles=1

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