EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
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Question
Chapter 2, Problem R27RQ
Program Plan Intro
Client:
In
Server:
In computer network, a server is a computer
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For the client-server application over TCP, why must the server program be executed before the client program? For the client server application over UDP, why may the client program be executed before the server program?
We have said that an application may choose UDP for a transport protocol because UDP
offers finer application control than TCP of what data is sent in a segment and when. Why
does an application have more control of what data is sent in a segment and when the segment
is sent?
An Internet banking application is implemented using the client server model and deployed over a wide area (Note: unreliable network). Consider the following two requests made by a client program to the server (i) Withdraw Ksh 40,000.00 and (ii) Get Balance. From your understanding of how TCP works, would it be a good decision to implement both operations using TCP? Explain!.
Chapter 2 Solutions
EBK COMPUTER NETWORKING
Ch. 2 - List five nonproprietary Internet applications and...Ch. 2 - Prob. R2RQCh. 2 - Prob. R3RQCh. 2 - Prob. R4RQCh. 2 - Prob. R5RQCh. 2 - Prob. R6RQCh. 2 - Prob. R7RQCh. 2 - Prob. R8RQCh. 2 - Prob. R9RQCh. 2 - Prob. R10RQ
Ch. 2 - Why do HTTP, SMTP, and POP3 run on top of TCP...Ch. 2 - Prob. R12RQCh. 2 - Prob. R13RQCh. 2 - Prob. R14RQCh. 2 - Prob. R15RQCh. 2 - Prob. R16RQCh. 2 - Prob. R17RQCh. 2 - From a users perspective, what is the difference...Ch. 2 - Prob. R19RQCh. 2 - Prob. R20RQCh. 2 - Prob. R21RQCh. 2 - Prob. R22RQCh. 2 - Prob. R23RQCh. 2 - Prob. R24RQCh. 2 - Prob. R25RQCh. 2 - In Section 2.7, the UDP server described needed...Ch. 2 - Prob. R27RQCh. 2 - Prob. P1PCh. 2 - Prob. P2PCh. 2 - Prob. P3PCh. 2 - Prob. P4PCh. 2 - Prob. P5PCh. 2 - Prob. P6PCh. 2 - Prob. P7PCh. 2 - Prob. P8PCh. 2 - Prob. P9PCh. 2 - Prob. P10PCh. 2 - Prob. P11PCh. 2 - Prob. P13PCh. 2 - Prob. P14PCh. 2 - Prob. P15PCh. 2 - Prob. P16PCh. 2 - Prob. P17PCh. 2 - Suppose you can access the caches in the local DNS...Ch. 2 - Prob. P21PCh. 2 - Prob. P22PCh. 2 - Prob. P23PCh. 2 - Prob. P25PCh. 2 - Prob. P26PCh. 2 - Prob. P27PCh. 2 - Prob. P28PCh. 2 - Prob. P29PCh. 2 - Prob. P30PCh. 2 - Prob. P31PCh. 2 - Prob. P32P
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Similar questions
- We have said that an application may choose UDP for a transport protocol because UDP offers finer application control (than TCP) of what data is sent in a segment and when. a. Why does an application have more control of what data is sent in a segment? b. Why does an application have more control on when the segment is sent?arrow_forwardBoth TCP and UDP are separate protocols that may be contrasted with one another. Give us an example of two situations in which you, as a software architect, might choose to make use of TCP rather than UDP.arrow_forwardWrite a Java TCP MultipleClient-Server Program for following scenario. NOTE Server Details are in the above figure Client-Server communicates continuously until the Client send Bye to the Server Use Multithreading for Multiple Clients NOTE : 1 cm = 0.39 inches 1 cm = 0.03 foot 1 cm = 0.01 meter Sample Ouput: Client Server 1 – cm to inches 2 – cm to foot 3 – cm to meter Enter length in cms (int) : 10 Received from Server 3.9 inches 1 – cm to inches 2 – cm to foot 3 – cm to meter Enter length in cms (int) : BYE Received from Server BYE Client DISCONNECTED Server Waiting for the Cline to be Connected… CONECTION ESTABLISHED Received From Client 10 cms Sent to Client 3.9 inches Received From Client BYE Sent to Client BYE HINT : When client choses 1 for cm to inches and enter 10, then the client sends the string 110 to the Server. Where the first char ‘1’ represents the cm to inches and the other 2 chars represents the 10.arrow_forward
- Consider a TCP connection between Host A and Host B and the transmission of a large file from A to B. If the buffer of host B is significantly smaller than the size of the buffer of host A and the file itself, what would be outcome?arrow_forwardQ1.Suppose a client, say C, has established a TCP connection with a server, say S. After establishing the connection, the sender sends two TCP messages with data back-to-back ( the first TCP message with sequence number 32 and the second TCP message with sequence number 100). a. What is the sequence number chosen by the client? What could be the reason for choosing this value of sequence number?b. What is the data size of first and second TCP data messages?c. Suppose the server receives the first and second TCP messages with data with the difference of 100 milliseconds delay. What could be the ACK number for both the TCP data messages from the server side as per the TCP RFC.arrow_forwardthe UDP server described needed only one socket, whereas the TCP server needed two sockets. Why? If the TCP server were to support n simultaneous connections, each from a different client host, how many sockets would the TCP server need?arrow_forward
- In HTTP version 1.0, a server marked the end of a transfer by closing the connection. Explain why, in terms of the TCP layer, this was a problem for servers. Find out how HTTP version 1.1 avoids this. How might a general-purpose request/reply protocol address this?arrow_forwardWhy might UDP be preferred over TCP in a given application?arrow_forwardTo what extent does the sliding window mechanism of TCP make use of TCP fields?arrow_forward
- Why might UDP be chosen over TCP in an application?arrow_forward2. Describe the diagram in sentences (What is happening in this diagram). Write a client-scrver paradigm program fragments (in Java) for this scenario. TCP Server TCP Client timestamparrow_forwardThree-way handshake is used by a TCP client and a TCP server to establish a connection, as illustrated below: 1st: client:port1 -> server:port2, SYN 2nd: server:port2 -> client:port1, SYNACK 3rd: client:port1 -> server:port2, ACK When this client is performing scanning attacks, it will generated a large number of failed connections. In each failed connection, the three-way handshake fails to complete. People commonly use SYN together with the absence of its corresponding SYNACK in this same TCP session to identify whether this connection is failed. By investigating the failed connections, an engineer finds that in legitimate/benign cases, if the server does not return SYNACK to the client, the client will not send the ACK packet after SYNACK (e.g., the 3rd packet above). Therefore, this engineer suggests that we can count the failed connections based on the following rules without considering SYNACK:arrow_forward
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