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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Sulfur forms a wide variety of compounds in which it has + 6, + 4, + 2, 0, and −2 oxidation states. Give examples of sulfur compounds having each of these oxidation states.

Interpretation Introduction

Interpretation: It is given that, sulfur exhibits many oxidation states (+6,+4,+2,0,2) . Examples of sulfur compounds having these oxidation states is to be given.

Concept introduction: Sulfur is a group 6A element. It exhibits different oxidation states.

Oxidation state is a number that is assigned to each element in a compound. This number describes the ability to loss or gain electrons.

To determine: The examples of sulfur compounds having (+6,+4,+2,0,2) oxidation states.

Explanation

Explanation

Sulfur compound having +6 oxidation state is SO3 .

Oxidation state of oxygen is 2 .

It is assumed that oxidation state of sulfur is x .

The compound SO3 contains three oxygen atoms. Since, stable molecule has zero overall charge. Therefore,

3(2)+x=0x=+6

Therefore, the oxidation state of sulfur in SO3 is +6 .

Sulfur compound having +4 oxidation state is SO2 .

Sulfur compound having +4 oxidation state is SO2 .

Oxidation state of oxygen is 2 .

It is assumed that oxidation state of sulfur is x .

The compound SO2 contains two oxygen atoms. Since, stable molecule has zero overall charge. Therefore,

2(2)+x=0x=+4

Therefore, the oxidation state of sulfur in SO2 is +4 .

Sulfur compound having +2 oxidation state is Na2S2O3 .

Sulfur compound having +2 oxidation state is Na2S2O3 .

Oxidation state of oxygen is 2 .

Oxidation state of sodium is +1

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