Determining the value of variables “first” and “last” in function “reverse_array”: From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2 Case 1: When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”. Then call the function “reverse_array” with “cnt = 1”. first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last]) first = 0 last = 1 - 1 = 0 0 < = 0 inplace_swap(&a[0], &a[0]) Here the both values are equal so value of middle element “a[0]” is “0”. Therefore, “first = 0” and “last = 0”. That is same as the value of “k”. Case 2: When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3. Then call the function “reverse_array” with “cnt = 3”...

Question

Want to see the full answer?

Answer 1

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Problem 15 (#2.3.30).If f and f◦g are one-to-one, does it follow that g must be one-to-one? Justify your answer.

3. The diagram below shows the main land routes for vehicular traffic between points A and G in a city. The figures in the arcs represent the cost of traveling between each pair of nodes. a) Manually apply Dijkstra's algorithm to find the cheapest route between A and G (visited nodes and total distance). b) Formulate a linear programming problem in extended form, to determine the shortest route to travel from A to G. Do not use subscripts, name 14 variables, for example XFE would be the variable that indicates that the arc from F to E is used. c) If there is a fixed cost for visiting each node, modify the formulation of the problem to include said fixed cost in the objective function, and the variables and restrictions that are required. NODE A B C D E F G FIXED COST 25 18 32 20 28 18 34

4.1.1 Complete solution and answer only no need explanation Given three data points (1,6), (3,28), and (10, 231), What is the value of y at x = 2 if the function y = 2x2 + 3x + 1 passes through the three data points.

Answer 2

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 8

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

Answer 9

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

Answer 10

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

Answer 11

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

Answer 12

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 13

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 2.1 - Practice Problem 2.1 (solution page 143) Perform...Ch. 2.1 - Prob. 2.2PP Ch. 2.1 - Prob. 2.3PP Ch. 2.1 - Practice Problem 2.4 (solution page 144) Without...Ch. 2.1 - Prob. 2.5PP Ch. 2.1 - Prob. 2.6PP Ch. 2.1 - Prob. 2.7PP Ch. 2.1 - Prob. 2.8PP Ch. 2.1 - Practice Problem 2.9 solution page 146 Computers...Ch. 2.1 - Prob. 2.10PP

Solution Summary: The author explains how to determine the value of variables "first" and "last" in function "reverse_array".

Concept explainers

Explanation of Solution

Explanation of Solution

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Want to see the full answer?

Chapter 2 Solutions

Solution Summary: The author explains how to determine the value of variables "first" and "last" in function "reverse_array".

Concept explainers

Explanation of Solution

Explanation of Solution

Explanation of Solution

Modification to the code for “reverse_array” function: Replace the test condition of “first <=...

Want to see the full answer?

Chapter 2 Solutions

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...