Concept explainers
Interpretation:
The strucutral formula of the given compound K has to be decucted with the help of the given
Concept Introduction:
The
Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound. Generally, tetramethylsilane (TMS) is taken as the reference compound. The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.
13C NMR Spectroscopy: This type of NMR splitting of signals tells us numbers of hydrogens atoms are attached to each carbon. The triangle rule (n+1) C. The chemical shift explains the different hybridization
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Chapter 21 Solutions
Organic Chemistry
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardCompound K, molecular formula C6H14O, readily undergoes acid-catalyzed dehydration when warmed with phosphoric acid to give compound L, molecular formula C6H12, as the major organic product. The 1H-NMR spectrum of compound K shows signals at d 0.90 (t, 6H), 1.12 (s, 3H), 1.38 (s, 1H), and 1.48 (q, 4H). The 13C-NMR spectrum of compound K shows signals at d 72.98, 33.72, 25.85, and 8.16. Deduce the structural formulas of compounds K and L.arrow_forwardWhen a compound with molecular formula C11H14O2 undergoes acid-catalyzed hydrolysis, one of the products that is isolated gives the following 1H NMR spectrum. Identify the compound.arrow_forward
- Please propose a structural formula for compound A, C4H10O, consistent with the following 1H-NMR and IR spectra. Assign all the appropriate peaks in the IR and NMR spectra and provide a short narrative describing what structural information each piece of data provided.arrow_forwardAn aromatic compound K, whose molecular formula is C8H11N, is examined in the laboratory to elucidate its structure. The following observations were made: A) Compound K is soluble in dilute hydrochloric acid but insoluble in sodium hydroxide solution. B) Treatment of compound K with excess potassium hydroxide and benzenesulfonyl chloride, C(6)H(5)SO(2)Cl, results in the formation of a heterogeneous mixture. The NMR spectrum of compound K is shown below. C) Compound K when treated with acetic anhydride[CH3-C(O)-O-C(O)-CH3], gives compound L, whose molecular formula is C(10)H(13)ON. Compound L is insoluble in dilute acid or dilute base at room temperature, heating compound L in dilute acid or base, however, regenerates compound K. D) When compound L is heated with a mixture of concentrated nitric acid and sulfuric acid, a single product, compound M, with the molecular formula C(10)H(12)O(3)N(2) is formed in excellent yields. On the basis of these observations draw the structures of…arrow_forwardPhenacetin is an analgesic compound having molecular formula C10H13NO2. Once a common component in over-the-counter pain relievers such as APC (aspirin, phenacetin, caffeine), phenacetin is no longer used because of its liver toxicity. Deduce the structure of phenacetin from its 1H NMR and IR spectra.arrow_forward
- Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.arrow_forwardA solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?arrow_forwardThymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.arrow_forward
- Compound P has molecular formula C5H9C102. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forwardAn unknown compound has a molecular formula of C4H6O2. Its IR spectrum shows absorptions at 3095, 1762, 1254, and 1118 cm -1. It exhibits the following signals in its 1H NMR spectrum (ppm): 2.12 (singlet,3H), 4.55 (doublets of doublets, 1H), 4.85 (doublet of doublets, 1H), 7.25 (doublets of doublets, 1H); and the following signals in its 13C NMR spectrum (ppm): 20.8, 100.4, 141.2, 168.0. Draw the structure of the unknown compoundarrow_forwardThe 1H-NMR spectrum of compound R, C6H14O, consists of two signals: d 1.1 (doublet) and d 3.6 (septet) in the ratio 6:1. Propose a structural formula for compound R consistent with this informationarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning