PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 2.1, Problem 2E

(a)

To determine

Percentile for Colorado with 10.1% of the residents are aged 65 and above.

(a)

Expert Solution
Check Mark

Answer to Problem 2E

Percentile for Colorado with 10.1% of the residents is 8th percentile.

Explanation of Solution

Given information:

Stemplot of the percents:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 2.1, Problem 2E , additional homework tip  1

Let

n , Number of data values that are less than the individual’s data value

N , Total number of data values

Now,

Write down all the data values from stemplot in ascending order:

Where,

  7|0represents7.0 .

7.0, 8.8, 9.8, 10.0, 10.1, 10.9, 11.1, 11.6, 11.7, 11.7, 11.7, 12.0, 12.1, 12.1, 12.2, 12.2, 12.4, 12.5, 12.6, 12.7, 12.7, 12.8, 12.9, 12.9, 12.9, 13.0, 13.0, 13.0, 13.1, 13.2, 13.2, 13.3, 13.3, 13.4, 13.4, 13.4, 13.5, 13.5, 13.6, 13.8, 13.9, 14.0, 14.2, 14.3, 14.5, 14.6, 14.8, 15.2, 15.4, 16.9.

Note that

4 of the 50 states have percentage below 10.1%.

Percentile can be determined as the number of data values that are less than the individual’s data value ( n ), divided by the total number of data values ( N ), written as percentage.

  Percentile=450×100%=0.08×100%=8%

Thus,

Percentile that corresponds with 10.1% of the residents is 8th percentile.

(b)

To determine

Interpretation of 80th percentile and percent of Rhode Island’s residents are aged 65 and above.

(b)

Expert Solution
Check Mark

Answer to Problem 2E

14% of Rhode Island’s residents are 65 or older and is at 80th percentile.

Explanation of Solution

Given information:

Stemplot of the percents:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 2.1, Problem 2E , additional homework tip  2

Let

n , Number of data values that are less than the individual’s data value

N , Total number of data values

Now,

Write down all the data values from stemplot in ascending order:

Where,

  7|0represents7.0 .

7.0, 8.8, 9.8, 10.0, 10.1, 10.9, 11.1, 11.6, 11.7, 11.7, 11.7, 12.0, 12.1, 12.1, 12.2, 12.2, 12.4, 12.5, 12.6, 12.7, 12.7, 12.8, 12.9, 12.9, 12.9, 13.0, 13.0, 13.0, 13.1, 13.2, 13.2, 13.3, 13.3, 13.4, 13.4, 13.4, 13.5, 13.5, 13.6, 13.8, 13.9, 14.0, 14.2, 14.3, 14.5, 14.6, 14.8, 15.2, 15.4, 16.9.

Note that

In the sample, there are total 50 states (or 50 data values).

Such that

  N=50

The data value represented by the xth percentile has x% of the data values below it.

If Rhode Island’s is at 80th percentile,

80th percentile has 80% of the data values below it.

Calculate 80% of 50 data values:

  n=80%×N=80100×50=45×50=40

We have

40 out of 50 data values below 80th percentile.

80th percentile needs to be the 41st data value in the ascending order, and that is 14.0.

Thus,

In Rhode Island’s, 14% of residents are 65 or older and is at 80th percentile.

Chapter 2 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54ECh. 2.2 - Prob. 55ECh. 2.2 - Prob. 56ECh. 2.2 - Prob. 57ECh. 2.2 - Prob. 58ECh. 2.2 - Prob. 59ECh. 2.2 - Prob. 60ECh. 2.2 - Prob. 61ECh. 2.2 - Prob. 62ECh. 2.2 - Prob. 63ECh. 2.2 - Prob. 64ECh. 2.2 - Prob. 65ECh. 2.2 - Prob. 66ECh. 2.2 - Prob. 67ECh. 2.2 - Prob. 68ECh. 2.2 - Prob. 69ECh. 2.2 - Prob. 70ECh. 2.2 - Prob. 71ECh. 2.2 - Prob. 72ECh. 2.2 - Prob. 73ECh. 2.2 - Prob. 74ECh. 2.2 - Prob. 75ECh. 2.2 - Prob. 76ECh. 2.2 - Prob. 77ECh. 2.2 - Prob. 78ECh. 2.2 - Prob. 79ECh. 2.2 - Prob. 80ECh. 2.2 - Prob. 81ECh. 2.2 - Prob. 82ECh. 2.2 - Prob. 83ECh. 2.2 - Prob. 84ECh. 2.2 - Prob. 85ECh. 2.2 - Prob. 86ECh. 2.2 - Prob. 87ECh. 2.2 - Prob. 88ECh. 2.2 - Prob. 89ECh. 2.2 - Prob. 90ECh. 2.2 - Prob. 91ECh. 2.2 - Prob. 92ECh. 2 - Prob. R2.1RECh. 2 - Prob. R2.2RECh. 2 - Prob. R2.3RECh. 2 - Prob. R2.4RECh. 2 - Prob. R2.5RECh. 2 - Prob. R2.6RECh. 2 - Prob. R2.7RECh. 2 - Prob. R2.8RECh. 2 - Prob. R2.9RECh. 2 - Prob. T2.1SPTCh. 2 - Prob. T2.2SPTCh. 2 - Prob. T2.3SPTCh. 2 - Prob. T2.4SPTCh. 2 - Prob. T2.5SPTCh. 2 - Prob. T2.6SPTCh. 2 - Prob. T2.7SPTCh. 2 - Prob. T2.8SPTCh. 2 - Prob. T2.9SPTCh. 2 - Prob. T2.10SPTCh. 2 - Prob. T2.11SPTCh. 2 - Prob. T2.12SPTCh. 2 - Prob. T2.13SPT
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