Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 22, Problem 22.33P
Interpretation Introduction
Interpretation:
The carbon atoms of palmitic acid that are radiolabeled are to be shown.
Concept Introduction:
Claisen condensation is a reaction in which two esters undergo condensation to form diketone or diester compounds. Claisen condensation also plays an important role in the biosynthesis of fatty acids from Acetyl-CoA.
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Chapter 22 Solutions
Organic Chemistry
Ch. 22 - Prob. 22.1PCh. 22 - Prob. 22.2PCh. 22 - Prob. 22.3PCh. 22 - Prob. 22.4PCh. 22 - Prob. 22.5PCh. 22 - Prob. 22.6PCh. 22 - Prob. 22.7PCh. 22 - Prob. 22.8PCh. 22 - Prob. 22.9PCh. 22 - Prob. 22.10P
Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17PCh. 22 - Prob. 22.18PCh. 22 - Prob. 22.19PCh. 22 - Prob. 22.20PCh. 22 - Prob. 22.21PCh. 22 - Prob. 22.22PCh. 22 - Prob. 22.23PCh. 22 - Prob. 22.24PCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Prob. 22.28PCh. 22 - Prob. 22.29PCh. 22 - Prob. 22.30PCh. 22 - Prob. 22.31PCh. 22 - Prob. 22.32PCh. 22 - Prob. 22.33PCh. 22 - Prob. 22.34PCh. 22 - Prob. 22.35PCh. 22 - Prob. 22.36PCh. 22 - Prob. 22.37PCh. 22 - Prob. 22.38PCh. 22 - Prob. 22.39PCh. 22 - Prob. 22.40PCh. 22 - Prob. 22.41PCh. 22 - Prob. 22.42PCh. 22 - Prob. 22.43PCh. 22 - Prob. 22.44PCh. 22 - Prob. 22.45PCh. 22 - Prob. 22.46PCh. 22 - Prob. 22.47PCh. 22 - Prob. 22.48PCh. 22 - Prob. 22.49PCh. 22 - Prob. 22.50PCh. 22 - Prob. 22.51PCh. 22 - Prob. 22.52PCh. 22 - Prob. 22.53PCh. 22 - Prob. 22.54PCh. 22 - Prob. 22.55APCh. 22 - Prob. 22.56APCh. 22 - Prob. 22.57APCh. 22 - Prob. 22.58APCh. 22 - Prob. 22.59APCh. 22 - Prob. 22.60APCh. 22 - Prob. 22.61APCh. 22 - Prob. 22.62APCh. 22 - Prob. 22.63APCh. 22 - Prob. 22.64APCh. 22 - Prob. 22.65APCh. 22 - Prob. 22.66APCh. 22 - Prob. 22.67APCh. 22 - Prob. 22.68APCh. 22 - Prob. 22.69APCh. 22 - Prob. 22.70APCh. 22 - Prob. 22.71APCh. 22 - Prob. 22.72APCh. 22 - Prob. 22.73APCh. 22 - Prob. 22.74APCh. 22 - Prob. 22.75APCh. 22 - Prob. 22.76APCh. 22 - Prob. 22.77APCh. 22 - Prob. 22.78APCh. 22 - Prob. 22.79APCh. 22 - Prob. 22.80APCh. 22 - Prob. 22.81APCh. 22 - Prob. 22.82APCh. 22 - Prob. 22.83APCh. 22 - Prob. 22.84APCh. 22 - Prob. 22.85APCh. 22 - Prob. 22.86APCh. 22 - Prob. 22.87APCh. 22 - Prob. 22.88APCh. 22 - Prob. 22.89APCh. 22 - Prob. 22.90APCh. 22 - Prob. 22.91APCh. 22 - Prob. 22.92APCh. 22 - Prob. 22.93APCh. 22 - Prob. 22.94APCh. 22 - Prob. 22.95APCh. 22 - Prob. 22.96APCh. 22 - Prob. 22.97APCh. 22 - Prob. 22.98AP
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- Aldohexoses A and B are formed from aldopentose C via a Kiliani–Fischer synthesis. Nitric acid oxidizes A to an optically active aldaric acid, B to an optically inactive aldaric acid, and C to an optically active aldaric acid. Wohl degradation of C forms D, which is oxidized by nitric acid to an optically active aldaric acid. Wohl degradation of D forms (+)-glyceraldehyde. Identify A, B, C, and D.arrow_forwardA D-aldopentose A is reduced to an optically active alditol. Upon Kiliani–Fischer synthesis, A is converted to two D-aldohexoses, B and C. B is oxidized to an optically inactive aldaric acid. C is oxidized to an optically active aldaric acid. What are the structures of A–C?arrow_forwardAssuming the oligopeptide ALPHAHELICKS forms one continuous alpha-helix, the carbonyl oxygen of the glutamic acid residue is hydrogen-bonded to the hydrogen in the amide nitrogen of??arrow_forward
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- There are three (3) vials labeled A, B, and C known to contain the following monosaccharides. All three samples reduce Tollens and Fehling. By oxidation with dilute HNO3 an optically active aldaric acid is obtained for sample A and the remaining two give products without optical activity. When the three samples were subjected to an alkaline medium, it was observed that, after a certain time, samples A and C reached the same value of the specific rotation [α]. Select the RIGHT alternative: (a) Sample A is Galactose. (b) Sample B is Alosa. (c) Samples A and C are not related to each other by an epimerization process. (d) Sample C is Talose. (e) Samples B and C are epimers.arrow_forward(i) Acetylation of glucose with acetic anhydride gives glucosepentaacetate. Write the structure of the pentaacetate.(ii) Explain why glucose pentaacetate does not react with hydroxylamine?arrow_forwardA hexose was obtained after (+)-glyceraldehyde underwent three successive Kiliani–Fischer syntheses. Identify the hexose from the following experimental information: oxidation with nitric acid forms an optically active aldaric acid; a Wohl degradation followed by oxidation with nitric acid forms an optically inactive aldaric acid; and a second Wohl degradation forms erythrose.arrow_forward
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