To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide. Concept introduction: Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are, Deprotonation of α carbon Attach of enolate ion with the aldehyde ( nucleophilic attack ) Protonation of the alkoxide ion to give aldol product Dehydration of the aldol addition product to form conjugated enone (aldol condensation product) Please note that aldol condensation product is formed at higher temperature . Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Question

Want to see the full answer?

Answer 1

Question

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Question

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Answer 6

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Answer 7

Chapter 22.3, Problem 22ATS

Interpretation Introduction

Interpretation:

To draw all four aldol condensation products formed when 2-butanone is heated in presence of aqueous sodium hydroxide.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

Deprotonation of α carbon

Attach of enolate ion with the aldehyde (nucleophilic attack)

Protonation of the alkoxide ion to give aldol product

Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note : Simple way to enter starting material for aldol condensation product is to find out the carbon-carbon double bond. Break the double bond and add hydrogen to one of the part (highlighted in red) with carbonyl group. To another part (highlighted in grey) add oxygen so that carbonyl is formed. This can be shown as,

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 22.1 - Prob. 1CC Ch. 22.1 - Prob. 2CC Ch. 22.1 - Prob. 3CC Ch. 22.1 - Prob. 1LTS Ch. 22.1 - Prob. 4PTS Ch. 22.1 - Prob. 5ATS Ch. 22.1 - Prob. 6CC Ch. 22.1 - Prob. 7CC Ch. 22.1 - Prob. 8CC Ch. 22.2 - Prob. 9CC

Want to see the full answer?

Chapter 22 Solutions