EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Chapter 2.3, Problem 21E
To determine

To divide (3x+2x3−9−8x2)÷(x2+1) using long division.

Expert Solution & Answer
Check Mark

Answer to Problem 21E

The quotient of given division is 2x−8 and remainder is x−1 .

Explanation of Solution

Given:

  (3x+2x3−9−8x2)÷(x2+1)

Concept Used:

Steps to follow before applying Long Division method:

  1. Write the terms of the dividend and divisor in descending powers of the variable.
  2. Insert placeholders with zero coefficients for missing powers of the variable.

Calculation:

To divide (3x+2x3−9−8x2)÷(x2+1) use long division method.

First arrange the terms of dividend and divisor in descending powers of the variable.

As,

  (2x3−8x2+3x−9)÷(x2+1)

Now inserting placeholders with zero coefficients for missing powers of the variable above division becomes:

  (2x3−8x2+3x−9)÷(x2+0x+1)

Thus, the division may be proceeded as:

  x2+0x+1)2x3−8x2+3x−9(2x−8                  2x3+0x2+2x_                          −8x2+x−9                        −8x2−0x−8_                                       x−1

Thus, dividing (3x+2x3−9−8x2) by (x2+1) quotient is 2x−8 and remainder is x−1 .

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Chapter 2.3, Problem 20E
Next
Chapter 2.3, Problem 22E

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10E
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Polynomials with Trigonometric Solutions (2 of 3: Substitute & solve); Author: Eddie Woo;https://www.youtube.com/watch?v=EnfhYp4o20w;License: Standard YouTube License, CC-BY
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