a.
To determine whether each value of
a.
Answer to Problem 6E
The value
Explanation of Solution
Given information:
The inequality is
Calculation:
Factor the above inequality.
Break the middle term.
Take common
Now, equate
Add 4 from both sides.
The x is greater than or equal to 4.
So,
And, the inequality is true if
Subtract 2 from both sides.
The x is less than or equal to
Now, the combine interval (where the inequality is true) is,
Thus,
So, the value
b.
To determine whether each value of
b.
Answer to Problem 6E
The value
Explanation of Solution
Given information:
The inequality is
Calculation:
From part(a).
The combine interval is
Thus,
So, the value
c.
To determine whether each value of
c.
Answer to Problem 6E
The value
Explanation of Solution
Given information:
The inequality is
Calculation:
From part(a).
The combine interval is
Thus,
So, the value
d.
To determine whether each value of
d.
Answer to Problem 6E
The value
Explanation of Solution
Given information:
The inequality is
Calculation:
From part(a).
The combine interval is
Thus,
So, the value
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning