EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Question
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Chapter 2.6, Problem 44E

(a)

To determine

To state: the domains of the given functions f and g .

(a)

Expert Solution
Check Mark

Answer to Problem 44E

The domain of f is (−∞,0)∪(0,2)∪(2,∞) and the domain of g (−∞,∞)

Explanation of Solution

Given information:

Consider f(x)=x2(x−2)x2−2x,g(x)=x

Calculation:

The domain is the set of x values for which the function is defined.

The domain of f:

  f(x)=x2(x−2)x2−2xx2−2x=0x(x−2)=0x=0,2

The domain of g:

  g(x)=x

Hence, the domain of f is (−∞,0)∪(0,2)∪(2,∞) and the domain of g (−∞,∞)

(b)

To determine

To sketch: the graphs of f and g.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given information:

Consider f(x)=x2(x−2)x2−2x,g(x)=x

Graph:

Draw the graphs of f and g .

  EBK PRECALCULUS W/LIMITS, Chapter 2.6, Problem 44E

(c)

To determine

To explain: the graphs of f and g may not show the difference in the their domains.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given information:

Consider f(x)=x2(x−2)x2−2x,g(x)=x

  f(x)=x2(x−2)x2−2x=x2(x−2)x(x−2)=x⇒f(x)=g(x)

By simplifying, f and g are equal.

Hence, the graphing utility does not show any difference in domains of f and g

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Chapter 2.6, Problem 43E
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Chapter 2.6, Problem 45E

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10E
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Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RECh. 2 - Prob. 56RECh. 2 - Prob. 57RECh. 2 - Prob. 58RECh. 2 - Prob. 59RECh. 2 - Prob. 60RECh. 2 - Prob. 61RECh. 2 - Prob. 62RECh. 2 - Prob. 63RECh. 2 - Prob. 64RECh. 2 - Prob. 65RECh. 2 - Prob. 66RECh. 2 - Prob. 67RECh. 2 - Prob. 68RECh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 13CTCh. 2 - Prob. 14CTCh. 2 - Prob. 15CTCh. 2 - Prob. 16CTCh. 2 - Prob. 17CTCh. 2 - Prob. 18CTCh. 2 - Prob. 1PSCh. 2 - Prob. 2PSCh. 2 - Prob. 3PSCh. 2 - Prob. 4PSCh. 2 - Prob. 5PSCh. 2 - Prob. 6PSCh. 2 - Prob. 7PSCh. 2 - Prob. 8PSCh. 2 - Prob. 9PSCh. 2 - Prob. 10PSCh. 2 - Prob. 11PSCh. 2 - Prob. 12PSCh. 2 - Prob. 13PS
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