EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Chapter 2.7, Problem 17E
To determine

ToSolve: The inequality (x+2)225 and graph the solution set.

Expert Solution & Answer
Check Mark

Answer to Problem 17E

Thesolution set of the given inequality is

  [7,3]

Graph of the solution set is

  EBK PRECALCULUS W/LIMITS, Chapter 2.7, Problem 17E , additional homework tip  1

Explanation of Solution

Given:

The inequality (x+2)225

Concept Used:

Solving an inequality means, finding all the values of the variable for which inequality satisfy.

Calculation:

Given the inequality (x+2)225

Simplifying the inequality, we have

  (x+2)225(x+2)2250

Consider

  (x+2)225=0(x+2)2=25

That is

  x+2=5 and  x+2=5

  x=7

and x=3

The key numbers are x=7 and  x=3

The test intervals are (,7) , (7,3) and  (3,)

Evaluating the left side of the inequality (polynomial value) for a xvalue in each test interval.

    Test Interval xvaluePolynomial Value Conclusion
    (,7)x=8(x+2)225=(8+2)225=(6)225=3625=11Positive
    (7,3)x=0(x+2)225=(0+2)225=(2)225=425=21Negative
    (3,)x=4(x+2)225=(4+2)225=(6)225=3625=11Positive

The inequality is satisfied for all the xvalues in the interval (7,3) .

At end points

At x=7 ,

  (x+2)225=(7+2)225=(5)225=2525=0

Inequality satisfies

At x=3 ,

  (x+2)225=(3+2)225=(5)225=2525=0

Inequality satisfies

Therefore, the solution set of the given inequality is [7,3]

Plotting all the points of the solutions set on the graph, we have:

  EBK PRECALCULUS W/LIMITS, Chapter 2.7, Problem 17E , additional homework tip  2

Conclusion:

Thesolution set of the given inequality is [7,3]

Graph of the solution set is

  EBK PRECALCULUS W/LIMITS, Chapter 2.7, Problem 17E , additional homework tip  3

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

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Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RECh. 2 - Prob. 56RECh. 2 - Prob. 57RECh. 2 - Prob. 58RECh. 2 - Prob. 59RECh. 2 - Prob. 60RECh. 2 - Prob. 61RECh. 2 - Prob. 62RECh. 2 - Prob. 63RECh. 2 - Prob. 64RECh. 2 - Prob. 65RECh. 2 - Prob. 66RECh. 2 - Prob. 67RECh. 2 - Prob. 68RECh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 13CTCh. 2 - Prob. 14CTCh. 2 - Prob. 15CTCh. 2 - Prob. 16CTCh. 2 - Prob. 17CTCh. 2 - Prob. 18CTCh. 2 - Prob. 1PSCh. 2 - Prob. 2PSCh. 2 - Prob. 3PSCh. 2 - Prob. 4PSCh. 2 - Prob. 5PSCh. 2 - Prob. 6PSCh. 2 - Prob. 7PSCh. 2 - Prob. 8PSCh. 2 - Prob. 9PSCh. 2 - Prob. 10PSCh. 2 - Prob. 11PSCh. 2 - Prob. 12PSCh. 2 - Prob. 13PS
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