COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 68QAP
To determine
(a)
The separation distance on the screen of the first bright fringe from the central bright fringe
To determine
(b)
The distance on the screen between the 2nd dark fringe from the central bright fringe
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Chapter 23 Solutions
COLLEGE PHYSICS
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- An American standard analog television picture (non-HDTV), also known as NTSC, is composed of approximately 485 visible horizontal lines of varying light intensity. Assume your ability to resolve the lines is limited only by the Rayleigh criterion, the pupils of your eyes are 5.00 min in diameter, and the average wavelength of the light coming from the screen is 550. nm. Calculate the ratio of the minimum viewing distance to the vertical dimension of the picture such that you will not be able to resolve the lines.arrow_forwardSuppose the single slit in Figure 38.4 is 6.00 cm wide and in front of a microwave source operating at 7.50 GHz. (a) Calculate the angle for the first minimum in the diffraction pattern. (b) What is the relative intensity l/lmax at 0 =- 15.0? (c) Assume two such sources, separated laterally by 20.0 cm, are behind the slit. What must be the maximum distance between the plane of the sources and the slit if the diffraction patterns are to be resolved? In this case, the approximation sin tan 8 is not valid because of the relatively small value of a/.arrow_forwardLight of wavelength 632.8 nm illuminates a single slit, and a diffraction pattern is formed on a screen 1.00 m from the slit. (a) Using the data in the following table, plot relative intensity versus position. Choose an appropriate value for the slit width a and, on the same graph used for the experimental data, plot the theoretical expression for the relative intensity IImax=sin22 where = (a sin )/. (b) What value of a gives the best fit of theory and experiment? Position Relative to Maximum (mm) Relative Intensity 0 1.00 0.8 0.95 1.6 0.80 3.2 0.39 4.8 0.079 6.5 0.003 8.1 0.036 9.7 0.043 11.3 0.013 12.9 0.000 3 14.5 0.012 16.1 0.015 17.7 0.004 4 19.3 0.000 3arrow_forward
- Assume light of wavelength 650 nm passes through two slits 3.00 m wide, with their centers 9.00 m apart. Make a sketch of the combined diffraction and interference pattern in the form of a graph of intensity versus = (a sin )/. You may use Figure 37.7 as a starting point.arrow_forwardA double slit produces a diffraction pattern that is a combination of single and double slit interference. Find the ratio of the width of the slits to the separation between them, if the first minimum of the single slit pattern falls on the fifth maximum of the double slit pattern. (This will greatly reduce the intensity of the fifth maximum.)arrow_forwardAnalysis of an interference effect in a clear solid shows that the wavelength of light in the solid is 329 nm. Knowing this light comes from a He-Ne laser and has a wavelength of 633 nm in air, is the substance zircon or diamond?arrow_forward
- What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0°?arrow_forwardWhat is the distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0°?arrow_forwardMonochromatic coherent light of amplitude E0 and angular frequency passes through three parallel slits, each separated by a distance d from its neighbor. (a) Show that the time-averaged intensity as a function of the angle is I()=Imax[1+2cos(2dsin)]2 (b) Explain how this expression describes both the primary and the secondary maxima. (c) Determine the ratio of the intensities of the primary and secondary maxima. Hint: See Problem 16.arrow_forward
- What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum for visible light?arrow_forwardIt is possible that there is no minimum in the interference pattern of a single slit. Explain why. Is the same true of double slits and diffraction gratings?arrow_forwardUsing the result of the problem above, calculate the distance between fringes for 633-nm light falling on double slits separated by 0.0800 mm, located 3.00 m from a screen as in Figure 27.56.arrow_forward
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